The velocity of the particle 4 at time, t = 2.83 s, is -14.1 m/s.
The given parameters;
m1 = 1.45 kg, v1(t) = (6.09m/s) + (0.299m/s^2) × t
m2 = 2.81 kg, v2(t) = (7.83m/s) + (0.357m/s^2) × t
m3 = 3.89 kg, v3(t) = (8.09m/s) + (0.405m/s^2) × t
m4 = 5.03kg
The velocity of the center mass of the particles is calculated as;
McmVcm = m1v1 + m2v2 +m3v3+m4v4
Vcm= m1v1 + m2v2 +m3v3 +m4v4/ Mcm
0 = m1v1 + m2v2 +m3v3 +m4v4/ Mcm
m1v1 + m2v2 +m3v3+m4v4 = 0
m4v4 = -(m1v1 + m2v2 +m3v3)
v4 =-(m1v1 + m2v2 +m3v3)/ m4
The velocity of particle 1 at time, t = 2.83 s;
vi = 6.09 + 0.299× 2.83
v1 = 6.94 m/s
The velocity of particle 3 at time, t = 2.83 s;
v2 = 7.83 + 0.357 × 2.83
v2 = 8.84 m/s
The velocity of particle 3 at time, t = 2.83 s;
v3 = 8.09 + 0.405 × 2.83
v3 = 9.24 m/s
The velocity of particle 3 at time, t = 2.83 s;
v4 = - (m1v1 + m2v2 + m3v3)/m4
v4 = -(1.45×6.94 + 2.81×8.84 + 3.89×9.24)/5.03
v4 = -14.4 m/s
Thus, the velocity of the particle 4 at time, t = 2.83 s, is -14.1 m/s.
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