The work done on the Puck by the applied force from the most positive to the most negative is c, b, a respectively.
According to Newton's second law of motion, the force applied to an object is directly proportional to the product of mass and acceleration of the object.
F = ma

The force applied to an object increases with increases in the velocity of the object.
In the given diagram, the resultant velocity of the puck is calculated as follows;
Figure a:

Figure b:

Figure c:

Thus, the work done on the Puck by the applied force from the most positive to the most negative is c, b, a respectively.
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Explanation:
Assuming constant density, the pressure at a depth h is:
P = Patm + ρgh
3 (1.013×10⁵ Pa) = 1.013×10⁵ Pa + (1025 kg/m³) (9.81 m/s²) h
h = 20.1 m
The energy that the man has gained in being lifted is 3000J which is in the form of potential energy.
<u>Explanation:</u>
Given:
Work done, W = 3000J
Height, h = 2.5m
Time, t = 0.4 seconds
Energy gained = ?
As the man gets lifted, it gains potential energy.
Potential energy will be equal to the work done by the elevator.
We know,
potential energy = mgh
Thus, the energy that the man has gained in being lifted is 3000J which is in the form of potential energy.