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PtichkaEL [24]
3 years ago
6

How are melting glaciers controllers of the future environment?

Physics
1 answer:
KatRina [158]3 years ago
4 0

Answer:

Explanation: Today, the increasing temperature is causing ice caps on Mount Kilimanjaro and ice sheets in Antarctica and Greenland to melt (Lovgren 2004a) (see Appendix 2). This has resulted in the rise in sea level, causing many problems to the nature balance. Cold water fish cannot survive and even coral reefs are dying as the water is becoming too warm. This causes problems for people fishing them as a food source and influences the fisheries in general. Besides, Lovgren (2004b) said that the rising sea level can have serious impacts on low-lying countries, some of which like Indian Ocean’s Maldives or Nile Delta could be submerged. Not only will fishing be affected but people will also have difficulties in finding higher ground for living.

An imbalance in nature’s food chain would be caused by global warming. As ice sheets melt in the Antarctic, the polar bears would be adversely affected since the temperature is too warm for them to live. “Polar bears are entirely dependent on sea ice, you lose sea ice, you lose polar bears” (Malcolm 2004). Additionally, the seal and sea lion population that would otherwise be controlled by polar bears as part of their diet would multiply and overpopulation may occur, causing many fishes being eaten and depleted. This depletion affects fisheries and people living in the northern hemisphere because they must then find other food sources which would be difficult as their main source of protein and food are fish.

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I’m which medium does sound travel fastest railroad track or across the room
blondinia [14]
The closer the particles, the more will be the propogation of sound waves. Room contains air molecules which are far away from each other. So it takes much time for one molecule of air to disturb the other one. But in case of solids, as particles are much closer(compared to fluids), disturbance generated by one molecule is quickly transmitted to the next molecule
3 0
3 years ago
what type of simple machine is shown in the diagram?write the length and height of slope in it. Please help ASAP!!!​
Akimi4 [234]

the machine shown in the diagram is called a tramp.

the height of the tramp is 5 and the length is 12

7 0
3 years ago
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When an atom that has no charge looses two electrons it becomes a
alex41 [277]

Answer: it becomes a positive ion

Explanation:

So, when an atom loses 2 electrons there will be no change in the number of neutrons. Therefore, an isotope will not form. Thus, it is concluded that when an atom with no charge loses two electrons, it becomes a positive ion.

8 0
3 years ago
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When a golf club hits a 0.0459 kg ball at rest, it exerts a 2380 N force for 0.00100 s. What is the speed of the ball afterwards
aksik [14]

Answer:

51.85m/s

Explanation:

Given parameters:

Mass of ball  = 0.0459kg

Force  = 2380N

Time taken  = 0.001s

Unknown:

Speed of the ball afterwards  = ?

Solution:

To solve this problem, we use Newton's second law of motion:

   F = m x \frac{v - u}{t}  

F is the force

m is the mass

v is the final velocity

u is the initial velocity

t is the time taken

        2380  = 0.0459 x \frac{v- 0}{0.001}  

        0.0459v  = 2.38

                   v = 51.85m/s

8 0
3 years ago
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A surgical microscope weighing 200 lb is hung from a ceiling by four springs with stiffness 25 lb/ft. The ceiling has a vibratio
Nikitich [7]

Answer:

If there is no damping, the amount of transmitted vibration that the microscope experienced is   = 5.676*10^{-3} \ mm

Explanation:

The motion of the ceiling is y = Y sinωt

y = 0.05 sin (2 π × 2) t

y = 0.05 sin 4 π t

K = 25 lb/ft  × 4  sorings

K = 100 lb/ft

Amplitude of the microscope  \frac{X}{Y}= [\frac{1+2 \epsilon (\omega/ W_n)^2}{(1-(\frac{\omega}{W_n})^2)^2+(2 \epsilon  \frac{\omega}{W_n})^2}]

where;

\epsilon = 0

W_n = \sqrt { \frac{k}{m}}

= \sqrt { \frac{100*32.2}{200}}

= 4.0124

replacing them into the above equation and making X the subject of the formula:

X = Y * \frac{1}{\sqrt{(1-(\frac{\omega}{W_n})^2)^2})}}

X = 0.05 * \frac{1}{\sqrt{(1-(\frac{4 \pi}{4.0124})^2)^2})}}

X = 5.676*10^{-3} \ mm

Therefore; If there is no damping, the amount of transmitted vibration that the microscope experienced is   = 5.676*10^{-3} \ mm

8 0
3 years ago
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