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3 years ago

Find the integer between 2.7 and 3.7

Mathematics

2 answers:

sergeinik [125]3 years ago

5 0

Answer:

Step-by-step explanation:

An Integer consists of positive integers, negative integers, and zero.

Positive integers include numbers such as: 1, 2, 3, 4, 5...

Negative integers include numbers such as: -1, -2, -3, -4, -5...

Zero includes 0

To find the number you're looking for, consider an integer that is greater than 2.7 and less than 3.7.

The only integer that fits this description is 3.

2.7 < 3 < 3,7

Salsk061 [2.6K]3 years ago

4 0

Answer:

3.2

Step-by-step explanation:

The distance of 2.7 and 3.7 to 3.2 is .5 each, thus it is the integer in between both numbers.

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What is the value of x? 6 8 10 12

oee [108]

Answer:

Its 8

Step-by-step explanation:

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3 years ago

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A cuboid has side lengths 3cm, 4cm and 7cm. A cylinder with a height double that of the longest side of the cuboid has the same

mart [117]

Step-by-step explanation:

Longest side of cuboid: 7cm

Height of cylinder:

2 × 7 = 14 cm

Volume of cuboid:

7x3x4=84 $cm^3$

Volume of cylinder:

$84=14\pi r^2 \\r=\sqrt{\frac{6}{\pi} } \ \ \ cm\\r=1.38 \ cm\\$

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3 years ago

Evaluate 4 - 2(a2 – b2)2 when a = 3 and b = 2.

Anton [14]

Answer:

-46

Step-by-step explanation:

4 - 2(a^2 – b^2)^2 =

= 4 - 2(3^2 – 2^2)^2

= 4 - 2(9 - 4)^2

= 4 - 2(5)^2

= 4 - 2(25)

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6 0

3 years ago

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The burning time of a very large candle is normally distributed with mean of 2500 hours and standard deviation of 20 hours. Find

dezoksy [38]

Answer: C.-1.5

Step-by-step explanation:

Given: The burning time of a very large candle is normally distributed with mean $(\mu)$ of 2500 hours and standard deviation $(\sigma)$ of 20 hours.

Let X be a random variable that represent the burning time of a very large candle.

Formula: $Z=\dfrac{X-\mu}{\sigma}$

For X = 2470

$Z=\dfrac{2470-2500}{20}\\\\\Rightarrow\ Z=\dfrac{-30}{20}\\\\\Rightarrow\ Z=\dfrac{-3}{2}\\\\\Rightarrow\ Z=-1.5$

So, the z-score they corresponds to a lifespan of 2470 hours. =-1.5

Hence, the correct option is C.-1.5.

7 0

3 years ago

Prove that for all integers a and b, if a mod 7 = 5 and b mod 7 = 6 then ab mod 7 = 2.

sergiy2304 [10]

Hello :
if : a ≡ 5 ( mod 7) ....(1)
b ≡ 6 ( mod 7) ...(2)
(1)×(2) : ab ≡ 30 ( mod 7)
but : 30 = 7×4 + 2 ..... so : 30 ≡ 2 ( mod 7)
then : ab ≡ 2 ( mod 7)

6 0

3 years ago