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2 years ago

Please help me to add more questions about clones, for my podcast tomorrow

Physics

1 answer:

tankabanditka [31]2 years ago

5 0

1. Yes, I have heard of cloning

2. I think that it is real/possible, but we don’t k ow much about it yet

3. I don’t believe celebrities have been cloned, we aren’t that advanced

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Explain how metallic atoms bond to form metallic compounds.

xz_007 [3.2K]

In metallic bonds, the valence electrons from the s and p orbitals of the interacting metal atoms delocalize. That is to say, instead of orbiting their respective metal atoms, they form a “sea” of electrons that surrounds the positively charged atomic nuclei of the interacting metal ions

4 0

2 years ago

Read 2 more answers

A toy rocket is launched straight up by using a spring. The rocket is initially pressed down on the spring so that the spring is

tigry1 [53]

Answer:

6.86 meters

Explanation:

Let the compression of the string be represented by x, and the height of projection of the toy rocket be represented by h.

So that;

x = 9 cm = 0.09 m

In its rest position (i.e before the launch), the spring has a stored potential energy which is given as;

PE = $\frac{1}{2}$ K $x^{2}$

= $\frac{1}{2}$ x 830 x $(0.09)^{2}$

= 415 x 0.0081

= 3.3615

The potential energy in the string = 3.36 Joules

Also,

PE = mgh

where: m is the mass, g is the gravitational force and h the height.

m = 50 g = 0.05 kg, g = 9.8 m $s^{-2}$

Thus,

PE = 0.05 x 9.8 x h

3.3615 = 0.05 x 9.8 x h

3.3615 = 0.49h

⇒ h = $\frac{3.3615}{0.49}$

= 6.8602

The height of the toy rocket would be 6.86 meters.

4 0

2 years ago

A 84.0 kg ice hockey player hits a 0.150 kg puck, giving the puck a velocity of 36.0 m/s. If both are initially at rest and if t

AysviL [449]

Answer: 3333333222135790075

Explanation:Set term u equal to initial velocity for simplicity

Set V equal to final velocity for simplicity

To begin this problem, one must look at the system to have multiple stages. These being before and after hitting the puck. In these first few steps, we look at BEFORE the human hits the puck

This collision is elastic because the puck and the human do not join together after interaction

Because the initial velocity of both the puck and the human are both 0, the terms on the left of the equal sign become 0

Solving for the final velocity of the human gives this formula. This number should be negative as the negative indicates the direction he is going (left)

The final velocity of the puck is already given in the problem

Because the ice is frictionless, the final velocity before hitting the puck is equal to the initial velocity after hitting the puck

Now we begin to look at the system AFTER the puck has been hit

Using the formula for final position allows us to solve for time it takes the puck to travel the distance given

Solve for time

We can now use the formula for the final position of the human to solve for the final answer

12nuewnfunw

Plugging in formulas from steps 5 and 9 gives the final answer

<h2>Again, this number should be negative as the negative sign denotes the direction the human is going. Because the problem does not ask for snijndij hinu9nub hvtj c v7 yf jhmb tfgnb nb fyhgbv </h2>

4 0

2 years ago

Determine the mass of a ball with a velocity of 40.0 m/s and a wavelength of 8.92 Ã 10-34 m.

posledela

The wavelength is equal to Planck's constant divided by the ball's momentum.
This means that:
lambda = h / p .............> equation I
Momentum = mass * velocity ............> equation II

Substitute by equation II in equation I, you get:
lambda = h / mv
Now, we are given:
lambda = 8.92 * 10^-34 m
Planck's constant = 6.625 * 10^-34
velocity = 40 m/sec

Substitute with these givens in the above equation to calculate the mass as follows:
8.92*10^-34 = (6.625*10^-34) / (40*m)
mass = 0.0185678 kg

4 0

2 years ago

If the period wave is 6 seconds what is its frequency

Lunna [17]

Answer:

.17Hz

Explanation:

The formula for frequency is f= 1/T , where T is the period.

f = 1/6 and 1/6 ≈ .17

3 0

2 years ago

Please help me to add more questions about clones, for my podcast tomorrow​

Please help me to add more questions about clones, for my podcast tomorrow