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Karolina [17]
3 years ago
8

You are driving at the speed of 27.7 m/s (61.9764 mph) when suddenly the car in front of you (previously traveling at the same s

peed) brakes and begins to slow down with the largest deceleration possible without skidding. Considering an average human reaction, you press your brakes 0.543 s later. You also brake and decelerate as rapidly as possible without skidding. Assume that the coefficient of static friction is 0.804 between both cars’ wheels and the road.
Physics
2 answers:
Greeley [361]3 years ago
8 0

there is no questions associated with this what are the questions that go with this senario


Bess [88]3 years ago
4 0

Answer:

8.1242 m/s^2

Remaining part of the question:

The acceleration of gravity is 9.8 m/s2 . Calculate the acceleration of the car in front of you when it brakes?

Explanation:

Frictional force allow as a  car to stop from motion, but it is also part of the the force required by the the car to move forward, It help keeps the tires from sliding on the road. if you are to correctly calculate the motion of  a body  across a surface, you must take into account  the interactions  between the body and the surface.

ma=μmg

The acceleration of the car can be calculated as

a=μg=(0.829)(9.8)=8.1242 m/s^2

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The electromagnetic wave that delivers a cellular phone callto
spin [16.1K]

Answer:

E=2.41\cdot 10^{-5} J

Explanation:

The intensity of an electromagnetic wave can be expressed in terms of the magnetic field using the next relationship:

I_{average}=\frac{cB_{0}^{2}}{2\mu_{0}} (1)

  • c is the speed of light (3*10⁸ m/s)
  • μ₀ is the permeability of free space (in vacuum ) (1.26*10⁻⁶ N/A²)
  • B₀ is the magnetic field

I_{average}=\frac{3\cdot 10^{8}(1.5\cdot 10^{-10})^{2}}{2\cdot 1.26\cdot 10^{-6}}

I_{average}=2.68\cdot 10^{-6} W/m^{2}

Now, let's define the relationship between power (P) and average intensity (I).

I_{average}=\frac{P}{A}

  • P is the power
  • A is the area crossed

So we can calculate the power.

P=I_{average}\cdot A=2.68\cdot 10^{-6}\cdot 0.20=5.37\cdot 10^{-7} W

Finally, energy is the product of P times time, so:

E=P\cdot t=5.37\cdot 10^{-7} \cdot 45=2.41\cdot 10^{-5} J

I hope it helps you!

5 0
3 years ago
PLEASE ANSWER ASAP!!!
Salsk061 [2.6K]

Answer:

if one bulb burns out the other will also turn off because they are connected to each other.

4 0
3 years ago
A 10.1 g bullet leaves the muzzle of a rifle with a speed of 425 m/s. What constant force is exerted on the bullet while it is t
PIT_PIT [208]

Answer

Force will be 1520.2604 N

Explanation:

We have given mass of the bullet m = 10.1 gram = 0.0101 kg

Distance S= 0.6 m

Final velocity v = 425 m/sec

Initial velocity u will be 0 m/sec

From third equation of motion v^2=u^2+2as

425^2=0^2+2\times a\times 0.6

a=150520.833m/sec^2

We know that force is given by F = ma

So force = 0.0101×150520.833 = 1520.2604 N

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Answer:

sorry, no

Explanation:

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