Answer:
Part a)
at t = 3.00 s

at t = 20.0 s

Part b)
at t = 3.00 s

at t = 20.0 s

Explanation:
The car starts at x = 0
Part a)
Now at t = 3.00 s
the position of the car is given as x = 25 m and its speed is given as v = 11 m/s
Now for average velocity we have



Now for average acceleration we have



Part b)
Now at t = 20.0 s
the position of the car is given as x = 385 m and its speed is given as v = 45 m/s
Now for average velocity we have



Now for average acceleration we have



<span>The numbers in front of the chemical formulas change so that the equation will be balanced</span>
Answer:
using the lens formula: 1/f = 1/u + 1/v
focal length f = -30 (negative because it is concave lens)
object distance u = 60
image distance v= unknown
1/-30 = 1/60 + 1/v
v = -20
So, the image is 20cm from lens (on the same side along with the object), and it is virtual (because of negative sign) and erect (concave lens must produce erect images).
Explanation:
As you can see in the picture, we want the swimmer to go on a straight line, so the speed of the water must be equal to the speed of the swimmer along the x-axis. We also know the value of v, so we can calculate the of the cosine of the angle (alpha) between Vx and V. Thanks to the fundamental relation of gioniometry (cos^2(x) + sin^2(x) = 1) we can find the sine of alpha and calculate Vy. With Vy we can calculate the time that the swimmer will use for reaching the dock: s = Vy * t => t = s/(Vy).
I'll let you do all the calculations, you just have to plug in values.