Answer:
1988 m
Explanation:
Range of a projectile
R = U²sin2∅/g...................... Equation 1
Where R = Range, U = Initial velocity, g = acceleration due to gravity, ∅ = Angle of projection.
Given: U = 150 m/s, ∅ = 60°
Constant: g = 9.8 m/s².
Substitute these values into equation 1
R = 150²(sin60°)/9.8
R = 22500(0.866)/9.8
R = 1988 m
Hence the Range of the projectile is 1988 m
Answer:
(3 ) friction hope this is correct
Answer:
P = 238475 N
Q = 181125
Explanation:
From the diagram attached below,
For the bridge to be at equilibrium,
Sum of upward force = sum of downward force
P+Q = 400000+19600
P+Q = 419600.................. Equation 1
Taking moment about support A
sum of clockwise moment = sum of anti clockwise moment.
400000(10-3)+19600(8-3) = Q(20-6)
2800000+98000 = 16Q
2898000 = 16Q
Q = 2898000/16
Q = 181125 N.
Substitute the value of Q into equation 1
P+181125 = 419600
P = 419600-181125
P = 238475 N.
Hence, support A exert a force of 238475 N and support B exert a force of 181125 N
Friction is the force that opposes motion.
<h3>What is friction?</h3>
The term friction refers to the force that hinders the movement of a surface over another. The frictional force depends on the nature of the surfaces in contact.
1) The two forces acting on the ball during the frictional force are the forward force and the frictional force.
2) The ball takes more time to roll down the incline in the presence of the cloth because of the increase in friction of the surface.
3) The students repeated the investigation there times in order to ensure accuracy of the results.
4) The energy of the ball changes from potential energy at the top of the ramp to kinetic energy as it rolls down the ramp.
Learn more about frictional force: brainly.com/question/1714663
