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Elis [28]
2 years ago
9

Three coins are tossed. Each coin has a Head and a Tail. Find the probability of getting three tails. Write answers as a simplif

ied FRACTION.
Mathematics
2 answers:
Semmy [17]2 years ago
7 0

Answer:

1/2 x 1/2 x 1/2 = 1/8

1/8

Step-by-step explanation:

Ket [755]2 years ago
3 0

Your answer would be 1/8.

The probability for getting a tail one time would be 1/2 because there are only 2 sides of a coin. Since tossing one coin doesn't affect the outcome of tossing the other coins, the probability for getting a tail on all of the coins is 1/2 each. We want this to happen 3 times, so the answer would be 1/2 × 1/2 × 1/2 = 1/8.

I hope this helps!

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A function f(x)=3x+12.
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If you're using the app, try seeing this answer through your browser:  brainly.com/question/2822258

_______________


•  Function:   f(x) = 3x + 12.


A.  Finding the inverse of f.

The composition of f with its inverse results in the identity function:

(f o g)(x) = x

f[ g(x) ] = x

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3 · g(x) = x – 12

              x – 12
g(x)  =  ⸺⸺
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________


B.  Verifying that the composition of f and g gives us the identity function:

•  \mathsf{(f\circ g)(x)}

\mathsf{=f\big[g(x)\big]}\\\\\\ \mathsf{=3\cdot \left(\dfrac{x}{3}-4\right)+12}\\\\\\&#10;\mathsf{=\diagup\hspace{-7}3\cdot \dfrac{x}{\diagup\hspace{-7}3}-3\cdot 4+12}\\\\\\&#10;\mathsf{=x-12+12}\\\\&#10;\mathsf{=x\qquad\quad\checkmark}


and also

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\mathsf{=g\big[f(x)\big]}\\\\\\ \mathsf{=\dfrac{f(x)}{3}-4}\\\\\\ \mathsf{=\dfrac{3x+12}{3}-4}\\\\\\&#10;\mathsf{=\dfrac{\diagup\hspace{-7}3\cdot (x+4)}{\diagup\hspace{-7}3}-4}\\\\\\&#10;\mathsf{=x+4-4}\\\\&#10;\mathsf{=x\qquad\quad\checkmark}

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= – 2          <span>✔
</span>

•  Call h the compositon of f and g. So,

h(x) = (f o g)(x)

h(x) = x


As you can see above, there is no restriction for h. Therefore, the domain of h is R (all real numbers).


I hope this helps. =)

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