3 years ago

Complex to Trigonometric:Z=√6+√2+2i

Mathematics

1 answer:

Alekssandra [29.7K]3 years ago

8 0

Answer:

z=6+2i maybe

Step-by-step explanation:

You might be interested in

14. Shaun has a bag with 12 yellow tiles and

yaroslaw [1]

3 should be added to the tiles

3 0

3 years ago

Simplify the expression. <br> 100^(1/2)-125^(1/3)<br> PLEASE HELP OFFERING 24 POINTS

Alecsey [184]

Type it into Google and it will solve for you.

100^(1/2)-125^(1/3) = 10-5 = 5

5 0

3 years ago

Kellie currently has an average of 75 in her English class. If her grade is the mean of all her assignments, what would a grade

andriy [413]

Answer:

I just summited it, it was "Her mean grade would go up".

Step-by-step explanation:

8 0

3 years ago

Given the position of the particle, what the position(s) of the particle when it’s at rest

choli [55]

The position function of a particle is given by:

$X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t$

The velocity function is the derivative of the position:

$\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}$

The particle will be at rest when the velocity is 0, thus we solve the equation:

$2t^2-9t-18=0$

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

$t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Substituting:

$\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}$

We have two possible answers:

$\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}$

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

$undefined$

6 0

1 year ago

10x is greater than or equal to 120 cm^2

Agata [3.3K]

Answer:

x greater than or equal to 12cm^2

Step-by-step explanation:

8 0

3 years ago

Complex to Trigonometric:Z=√6+√2+2i​

Complex to Trigonometric:Z=√6+√2+2i