Medication is prescribed in 6 out of every 10 hospital emergency room visits that involve an injury. If a large urban hospital h
ad 930 emergency room visits involving an injury in the past month, how many of these visits would you expect included a prescription for medication?
We can first get the percentage of the emergency room visits that involves an injury. 6 out of 10. This will be (6/10)×100 = 60%
So, if there are 930 emergency room visits, the expected visits <span>included a prescription for medication is; </span> 60% of 930 = 60/100 × 930 = 0.6 ×930 = 558
The empirical rule tells you 68% of the distribution is within 1 standard deviation, so p(z > 1) ≈ 0.17. This means the z value is more than 1 for the probability to drop to 0.08. The only choice that is greater than 1 is 1.41. (The number is actually about 1.40507.)