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lana66690 [7]
3 years ago
9

In the following diagram, the voltage is 15 volts and the resistance is 3.0 ohms. Use Ohm's law to determine the curre

Biology
1 answer:
weqwewe [10]3 years ago
3 0

Answer:

Explanation:

V = 15 volts

R = 3 ohms

I = ?

Formula

V = I  *  R

15 = I * 3

15/3 = I

5 = AMPS

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Vitamins help enzymes function as _____. A.proteins <br> B.coenzymes <br> C. minerals <br> D.fats
vekshin1
Vitamins help them function as fats.
4 0
3 years ago
Bees see the colors yellow and blue, but not red. Flowers that need to be pollinated by bees are mostly yellow of blue. What typ
Inga [223]

Answer:

Natural Selection

Explanation:

In natural selection process of evolution, traits that are essential for an individual to be fit enough to survive under environmental stress become dominant.

Since the flowers are of blue or yellow color, it is essential for a bee to be able enough to perceive the blue and yellow color. Hence, the eyes of bee with time have evolved to perceive these two color so that they can pollinate flower.

5 0
3 years ago
When pink sweet peas were self-pollinated and the seeds were collected and sown, the following flower colors were obtained: Red
Pavlova-9 [17]

Answer:

c. 1:2:1

The results are consistent with incomplete dominance for this trait, with pink flowers being heterozygous.

Explanation:

If flower color were determined by a gene showing incomplete dominance, the possible genotypes and phenotypes are as follows:

  • RR- red
  • ww - white
  • Rw - pink

If pink sweet peas are self-pollinated, then a cross between two heterozygous individuals is done (Rw x Rw).

<u>From this cross the expected ratios are:</u>

  • 1/4 RR (red)
  • 2/4 Rw (pink)
  • 1/4 ww (white)

So the null hypothesis is that the observed results exhibit a 1:2:1 ratio.

<h3><u>Chi square test</u></h3>

X^{2} = \sum \frac{(Observed - Expected)^2}{Expected}

<u>The observed frequencies were:</u>

  • 34 Red
  • 76 Pink
  • 40 White

Total 150

<u>The expected frequencies for our null hypothesis are:</u>

  • 1/4 x 150 = 37.5 Red
  • 2/4 x 150 = 75 Pink
  • 1/4 x 150 = 37.5 white

X^{2} = \frac{(34- 37.5)^2}{37.5} + \frac{(76- 75)^2}{75} + \frac{(40- 37.5)^2}{37.5}

X^2=0.5067

The degrees of freedom (DF) are calculated as number of phenotypes - 1; in this case DF = 3-1 = 2.

If we look at the Chi square table, for 2 DF and a probability of p0.05, the critical value is 5.991

Our X^2 value of 0.5067 is less than the critical value, so we do not reject the null hypothesis. The results are consistent with incomplete dominance for this trait, with pink flowers being heterozygous.

8 0
3 years ago
Consider three different species of wild cats. Populations of species A are spread evenly across Africa, species B is scattered
kvasek [131]

Answer:

a is DA answer

Explanation:

8 0
3 years ago
In the family tree below, people with the recessive trait of attached earlobes
Law Incorporation [45]

Answer:  D) it is a female with two recessive alleles

Explanation:

Since the shape is a circle, we know it is a female. Since the shape is shaded, we know the posses the recessive trait, meaning they must have two of it's alleles.

5 0
3 years ago
Read 2 more answers
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