Answer:
10⁻¹² W / m²
Explanation:
The feeble sound that a man can hear is of the vale which measures 0 on decibel scale . The intensity of sound in terms of J / m² .s is 10⁻¹² W / m² .
So the intensity of sound of monkey at 2.5 km must be 10⁻¹² W / m² .
Answer:
λ = 5.65m
Explanation:
The Path Difference Condition is given as:
δ=
;
where lamda is represent by the symbol (λ) and is the wavelength we are meant to calculate.
m = no of openings which is 2
∴δ= 
n is the index of refraction of the medium in which the wave is traveling
To find δ we have;
δ= 
δ= 
δ= 
δ= 
δ= 
δ= 
δ= 82.15 -73.68
δ= 8.47
Again remember; to calculate the wavelength of the ocean waves; we have:
δ= 
δ= 8.47
8.47 = 
λ = 
λ = 5.65m
Answer:
fundamental quantity can simply be defined as an independent quantity while derived quantity is dependent i.e. the derive their quantities from the fundamental
Answer:
s = 0.337 m
Explanation:
First, we will find the angular displacement of the reel:

where,
θ = angular displacement = ?
ω = angular speed = 1.9 rad/s
t = time taken = 7.1 s
Therefore,
θ = (1.9\ rad/s)(7.1 s)
θ = 13.5 rad
Now, we will find out the length of tape:
s = rθ
where,
s = length of tape = ?
r = radius of reel = 2.5 cm = 0.025 m
Therefore,
s = (0.025 m)(13.5 rad)
<u>s = 0.337 m</u>