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Liono4ka [1.6K]
3 years ago
7

Solve the pair of simultaneous equation 2-4(3x-y)=8(4-y)-39x and 8(4-y)-39x=6(y-x)

Mathematics
1 answer:
andre [41]3 years ago
8 0

Answer:

X = -(146/123) , Y = 21/41

Step-by-step explanation:

  • 2-4(3x-y) = 8(4-y)-39x

2-12x-4y = 32-8y-39x

39x-12x+8y-4y = 32-2

27x+4y = 30

27x+4y-30 = 0

  • 8(4-y) -39x = 6(y-x)

32-8y-39x = 6y-6x

32-8y-6y-39x+6x = 0

-33x-14y+32 = 0

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