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3 years ago

Solve the pair of simultaneous equation 2-4(3x-y)=8(4-y)-39x and 8(4-y)-39x=6(y-x)

Mathematics

1 answer:

andre [41]3 years ago

8 0

Answer:

X = -(146/123) , Y = 21/41

Step-by-step explanation:

2-4(3x-y) = 8(4-y)-39x

2-12x-4y = 32-8y-39x

39x-12x+8y-4y = 32-2

27x+4y = 30

27x+4y-30 = 0

8(4-y) -39x = 6(y-x)

32-8y-39x = 6y-6x

32-8y-6y-39x+6x = 0

-33x-14y+32 = 0

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2 years ago

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boyakko [2]

Hi Dezariaspencer

All we have to do is simply add 2x to both sides and we have our answer.

Answer: y = 11 + 2x.

Thank you for asking your question, have a good day.

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