The parallelogram ABCD is translated 7 units to the left to create A'B'C'D'.
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X Y
————-
-2. -4
-1. -8
0. -12
1. -16
2. -20
Answer:

Step-by-step explanation:
See comment for complete question
Given:


Required
The information that shows
by SSS
By SSS implies that, the three sides of both triangles are congruent
Already, we have:


The third side of
is 
The third side of
is 
So, for both to be congruent by SSS, the third sides must be congruent
i.e.

Answer:
-19/132
Step-by-step explanation:
To add fractions, find the lowest common multiple of the two denominators and multiply accordingly to make both denominators the same. In this case, the lowest common multiple of 11 and 12 is 132, so we need to multiply the first number by 12 and the second by 11. So we get
=
=

Answer:
We have the equation:
(ax^2 + 3x + 2b) - (5x^2+bx-3c)= 3x^2 - 9
First, move all to the left side.
(ax^2 + 3x + 2b) - (5x^2+bx-3c) - 3x^2 + 9 = 0
Now let's group togheter terms with the same power of x.
(a - 5 - 3)*x^2 + (3 - b)*x + (2b + 3c + 9) = 0.
This must be zero for all the values of x, then the things inside each parenthesis must be zero.
1)
a - 5 - 3 = 0
a = 3 + 5 = 8.
2)
3 - b = 0
b = 3.
3)
2b + 3c + 9 = 0
2*3 + 3c + 9 = 0
3c = -6 - 9 = -15
c = -15/3 = -5
Then we have:
a = 8, b = 3, c = -5
a + b + c = 8 + 3 - 5 = 6