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victus00 [196]
3 years ago
14

I need to get rid of the parenthesis and match like terms of -5(2x-3y)+2(x+2y)

Mathematics
2 answers:
irga5000 [103]3 years ago
5 0

Answer:

-8x + 19y

Step-by-step explanation:

distribute the -5

-10x + 15y + 2(x + 2y)

distribute the 2

-10x +15y + 2x + 4y

arange  the terms

-10x + 2x + 15y + 4y

combine

-8x + 19y

kakasveta [241]3 years ago
4 0

Answer:

-8x+19y

Step-by-step explanation:

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Help?<br><br> a) 2/10 + 8/100<br> b) 13/100 + 4/10<br> c) 6/10 + 39/100<br> D) 70/100 + 3/10
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3 years ago
3. A balancing balloon toy is in the shape of a hemisphere (half-sphere) attached to the base of a cone. If the toy is 4ft tall
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Answer:

The volume of the toy is V=5.23\ ft^3

Step-by-step explanation:

step 1

Find the volume of the hemisphere

The volume of the hemisphere is given by the formula

V=\frac{2}{3}\pi r^{3}

In this problem, the wide of the toy is equal to the diameter of the hemisphere

so

D=2\ ft

r=2/2=1\ ft ----> the radius is half the diameter

substitute

V=\frac{2}{3} \pi (1)^{3}=\frac{2}{3} \pi\ ft^3

step 2

Find the volume of the cone

The volume of the cone is given by

V=\frac{1}{3}\pi r^{2}h

we know that

The radius of the cone is the same that the radius of the hemisphere

so

r=1\ ft

The height of the cone is equal to subtract the radius of the hemisphere from the height of the toy

h=4-1=3\ ft

substitute the given values

V=\frac{1}{3}\pi (1)^{2}(3)=\pi\ ft^3

step 3

Find the volume of the toy

we know that

The volume of the toy, is equal to the volume of the cone plus the volume of the hemisphere.

so

V=(\frac{2}{3} \pi+\pi)\ ft^3

V=(\frac{5}{3}\pi)\ ft^3

assume

\pi=3.14

V=\frac{5}{3}(3.14)=5.23\ ft^3

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