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3 years ago

12 times the square root of 8737

Engineering

1 answer:

mixer [17]3 years ago

3 0

12 times the square root of 8737 is 1121.66305101

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Roman55 [17]

Answer:

i dont understand

Explanation:

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4 years ago

You recall an algorithm from elementary school for factoring a number N: Divide out all factors of 2, then of 3, then of 4, then

Contact [7]

Answer:

let number = 0

while number < 1

begin

print "Enter a positive integer: "

read number

end

end_while

find and print number's factors:

let prime = TRUE

let currentFactor = 2

let lastFactor = the square root of number truncated

to an integer value

while currentFactor <= lastFactor

begin

if number is evenly divisible by currentFactor

begin

print currentFactor

let number = number / currentFactor

end

else

let currentFactor = currentFactor + 1

end_if

end

end_while

print a message if number is prime:

if prime == TRUE

print "Your number is prime"

end_if

Explanation:

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3 years ago

Consider a voltage v = Vdc + vac where Vdc = a constant and the average value of vac = 0. Apply the integral definition of RMS t

Anna11 [10]

Answer:

Proof is as follows

Proof:

Given that , $V = V_{ac} + V_{dc}$

<u>for any function f with period T, RMS is given by</u>

<u /> $RMS = \sqrt{\frac{1}{T}\int\limits^T_0 {[f(t)]^{2} } \, dt }$ <u />

In our case, function is $V = V_{ac} + V_{dc}$

$RMS = \sqrt{\frac{1}{T}\int\limits^T_0 {[V_{ac} + V_{dc}]^{2} } \, dt }$

Now open the square term as follows

$RMS = \sqrt{\frac{1}{T}\int\limits^T_0 {[V_{ac}^{2} + V_{dc}^{2} + 2V_{dc}V_{ac}] } \, dt }$

Rearranging terms

$RMS = \sqrt{\frac{1}{T}\int\limits^T_0 {V_{dc}^{2} } \, dt + \frac{1}{T}\int\limits^T_0 {V_{ac}^{2} } \, dt + \frac{1}{T}\int\limits^T_0 {2V_{dc}V_{ac} } \, dt }$

You can see that

second term is square of RMS value of Vac

Third terms is average of VdcVac and given is that average of $V_{ac}V_{dc} = 0$

$RMS = \sqrt{\frac{1}{T}TV_{dc}^{2} + [RMS~~ of~~ V_{ac}]^2 }$

$RMS = \sqrt{V_{dc}^{2} + [RMS~~ of~~ V_{ac}]^2 }$

So it has been proved that given expression for root mean square (RMS) is valid

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