Answer:
A) attached below
B) 743 KJ
C) 1.8983 KJ/K
Explanation:
A) Diagram of system schematic and set up states
attached below
<u>B) Calculate the amount of work received from the paddle wheel </u>
assuming ideal gas situation
v1 = v2 ( for a constant volume process )
work generated by paddle wheel = system internal energy
dw = mCv dT . where ; Cv = 0.743 KJ/kgk
= 5 * 0.743 * ( 500 - 300 )
= 3.715 * 200 = 743 KJ
<u>C) calculate the amount of entropy generated ( KJ/K )</u>
S2 - S1 = 1.8983 KJ/K
attached below is the detailed solution
Answer:
The inventor's claim is false in the sense that no thermal machine can violate the first thermodynamic law.
Explanation:
The inventor's claim could not be possible as no thermal machine can transfer more heat than the input work consumed. If we expose the thermal efficiency:
Where Q and W both must be in the same power unit, so we will convert the remove heat from BTU/hr to hp:
Therefore by comparing, we notice that the removing heat of 4.75 hp is large than the delivered work of 1.11 hp. By evaluating the efficiency:
[tex]n=4.75 hp / 1.1 hp = 4.3 > 1[/tex]