Answer:
222.5 Gpa
Explanation:
From definition of engineering stress, 
where F is applied force and A is original area
Also, engineering strain,
where l is original area and
is elongation
We also know that Hooke's law states that 
Since A=20 mm* 20 mm= 0.02 m*0.02 m
F= 89000 N
l= 100 mm= 0.1 m

By substitution we obtain

Answer:
Explanation:
Given data in question
mean stress = 50 MPa
amplitude stress = 225 MPa
to find out
maximum stress, stress ratio, magnitude of the stress range.
solution
we will find first maximum stress and minimum stress
and stress will be sum of (maximum +minimum stress) / 2
so for stress 50 MPa and 225 MPa
=
+
/ 2
50 =
+
/ 2 ...........1
and
225 =
+
/ 2 ...........2
from eqution 1 and 2 we get maximum and minimum stress
= 275 MPa ............3
and
= -175 MPa ............4
In 2nd part we stress ratio is will compute by ratio of equation 3 and 4
we get ratio =
/
ratio = -175 / 227
ratio = -0.64
now in 3rd part magnitude will calculate by subtracting maximum stress - minimum stress i.e.
magnitude =
-
magnitude = 275 - (-175) = 450 MPa
Answer:
Explanation:
Obtain the following properties at 6MPa and 600°C from the table "Superheated water".

Obtain the following properties at 10kPa from the table "saturated water"

Calculate the enthalpy at exit of the turbine using the energy balance equation.

Since, the process is isentropic process 

Use the isentropic relations:

Calculate the enthalpy at isentropic state 2s.

a.)
Calculate the isentropic turbine efficiency.

b.)
Find the quality of the water at state 2
since
at 10KPa <
<
at 10KPa
Therefore, state 2 is in two-phase region.

Calculate the entropy at state 2.

Calculate the rate of entropy production.

since, Q = 0

Answer:
0.5m^2/Vs and 0.14m^2/Vs
Explanation:
To calculate the mobility of electron and mobility of hole for gallium antimonide we have,
(S)
Where
e= charge of electron
n= number of electrons
p= number of holes
mobility of electron
mobility of holes
electrical conductivity
Making the substitution in (S)
Mobility of electron


Mobility of hole in (S)


Then, solving the equation:
(1)
(2)
We have,
Mobility of electron 
Mobility of hole is 