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3 years ago

9

Ramesh took 30 minutes to jog from home home to a nearby park at a speed of 100 m/min.He took 5 minutes lesser to jog home from

the park via the same route.At what speed did he jog home from the park?

1 answer:

vaieri [72.5K]3 years ago

6 0

I'm pretty sure he was going 125 m/min

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The data below represents the number of customers at each Slurpee Sam's Spaghetti Shop. 24, 25, 29, 30, 31, 31, 32, 34, 34. Whic

NeX [460]

Answer:

A summary of the data is as follows;

1. Maximum = 34

2. Minimum = 24

3. The 1st quartile is 27

4. The median is or the 2nd quartile 34

5. The 3rd quartile is 33

The data is summarized in the attached box plot

Step-by-step explanation:

24, 25, 29, 30, 31, 31, 32, 34, 34

From the given data, we have the five values of a box and whisker plot as follows;

1. Maximum = 34

2. Minimum = 24

3. The 1st quartile is the $\frac{9 + 1}{4} th$ term or 27

4. The median (2nd quartile) is the $\frac{9 + 1}{2} th$ term or 34

5. The 3rd quartile is the $\frac{3(9 + 1)}{4} th$ term or 33

Hence the attached box plot summarizes the data.

6 0

3 years ago

An airline's public relations department claims that when luggage is lost, 88% is recovered and delivered to its owner within 24

melisa1 [442]

Answer:

The hypothesis statements are: H0: p = 0.88 versus HA : p < 0.88

The p-value of the test is 0.2483 > 0.1, which means that the data does not provide sufficient evidence to conclude that the proportion of times that luggage is returned within 24 hours is less than 0.88.

Step-by-step explanation:

Test if the proportion of times that luggage is returned within 24 hours is less than 0. 88

At the null hypothesis, we test if the proportion is of 0.88, that is:

$H_0: p = 0.88$

At the alternate hypothesis, we test if this proportion is less than 0.88, that is:

$H_a: p < 0.88$

The hypothesis statements are: H0: p = 0.88 versus HA : p < 0.88

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.88 is tested at the null hypothesis:

This means that $\mu = 0.88, \sigma = \sqrt{0.88*0.12}$

A consumer group who surveyed a large number of air travelers found that 138 out of 160 people who lost luggage on that airline were reunited with the missing items by the next day.

This means that $n = 160, X = \frac{138}{160} = 0.8625$

Test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.8625 - 0.88}{\frac{\sqrt{0.88*0.12}}{\sqrt{160}}}$

$z = -0.68$

P-value of the test:

The p-value of the test is the probability of finding a sample proportion below 0.8625, which is the p-value of z = -0.68.

Looking at the z-table, the p-value of z = -0.68 is of 0.2483.

The p-value of the test is 0.2483 > 0.1, which means that the data does not provide sufficient evidence to conclude that the proportion of times that luggage is returned within 24 hours is less than 0.88.

7 0

3 years ago

Factorise fully the following:<br> a) x² - 2x<br> b) 6x^2+ 12x<br> c) 3x^3- 9x<br> d) 4x^2+ 28x^3

mezya [45]

Answer:

a) x(x - 2)

b) 6x(x + 2)

c) 3x(x^2-3)

d) (2x)(2x)(1+7x)

Step-by-step explanation:

8 0

3 years ago

What is true when a system of equations has infinitely many solutions?

hjlf

B. The lines coincide

4 0

3 years ago

How is the graph of the parent quadratic function transformed to produce the graph of y = negative (2 x + 6) squared + 3?

bearhunter [10]

We start with the parent function

$f(x)=x^2$

The first child function would be

$g(x)=(2x)^2$

We have multiplied the input of the function by a constant: we have

$g(x)=f(2x)$

This kind of transformation result in a horizontal stretch/compression. If the multiplier is greater than 1, we have a compression. So, this first child causes a horizontal compression with compression rate 2.

The second child function would be

$h(x)=(2x+6)^2$

We added 6 to the input of the function: we have

$h(x)=g(x+6)$

This kind of transformation result in a horizontal translation. If the constant added is positive, we translate to the left. So, this second child causes a translation 6 units to the left.

The third child function would be

$l(x)=-(2x+6)^2$

We changed the sign of the previous function (i.e. we multiplied it by -1): we have

$l(x)=-h(x)$

This kind of transformation result in a vertical stretch/compression. If the multiplier is greater than 1 we have a stretch, if it's between 0 and 1 we have compression. If it's negative, we reflect across the x axis, and then apply the stretch/compression. In this case, the multiplier is -1, so we only reflect across the x axis.

The fourth child function would be

$m(x)=-(2x+6)^2+3$

We added 3 to previous function: we have

$m(x)=l(x)+3$

This kind of transformation result in a vertical translation. If the constant added is positive, we translate upwards. So, this last child causes a translation 3 units up.

Recap

Starting from the parent function $y=x^2$ , we have to:

Compress the graph horizontall, with scale factor 2;
Translate the graph 6 units to the left;
Reflect the graph across the x axis;
Translate the graph 3 units up

Note that the order is important!

5 0

3 years ago

Read 2 more answers