According to Newton’s second law of motion:
F=ma
=80*0.5
=40N
What is the strength of the electric field between two parallel conducting plates separated by 1.00 cm and having a potential difference (voltage) between them of 1.50×10^4v ?
Answer:
v = 20.31 m/s
Explanation:
p = mv -> v = p/m = 32,500 kg*m/s / 1,600 kg = 20.31 m/s
