Answer:
Imp_{1-2}=5000[kg*m/s]
Explanation:
In order to solve this problem, we must use the principle of conservation of momentum, which is defined as the product of mass by Velocity.
It must be defined that the impulse after the force is applied is equal to the momentum before the impulse applied on the body.
ΣPbefore = ΣPafter
P = momentum = m*v [kg*m/s]
In this way, we will construct the following equation.

where:
m₁ = mass of the object = 200 [kg]
v₁ = velocity of the object before the impulse = 15 [m/s]
v₂ = velocity of the object after the impulse = 40 [m/s]
Now replacing:
![(200*15) + Imp_{1-2} = (200*40)\\Imp_{1-2}=5000[kg*m/s]](https://tex.z-dn.net/?f=%28200%2A15%29%20%2B%20Imp_%7B1-2%7D%20%3D%20%28200%2A40%29%5C%5CImp_%7B1-2%7D%3D5000%5Bkg%2Am%2Fs%5D)
Answer:
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Explanation:
A force of 500N acts on the area of 2.5m2; calculate the pressure
exerted,
(Ans: 200 Pa]
b. Calculate the force applied when 400 Pa of pressure is exerted by a box
of surface area 2m2.
(Ans: 800 N]
The weight of a stone is 1400N. If it exerts a pressure of 700 Pa, calculate
the area.
(Ans: 2m]
d. A force of 2000 N acts on 5m² surface area. Calculate the pressure
exerted.
(Ans: 400 Pa]
c.
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