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Agata [3.3K]
3 years ago
8

A rectangular coil with sides 0.130 m by 0.250 m has 513 turns of wire. It is rotated about its long axis in a uniform magnetic

field of 0.550 T that is perpendicular to the long axis. At what frequency, in complete cycles per second, must the coil be rotated for it to generate a maximum voltage of 115 V?
Physics
1 answer:
Sonbull [250]3 years ago
3 0
Voltage = N * Δ(BA)/Δt 
<span>BA = 0.57*0.16*0.22 = 2.0064e-2 </span>
<span>N = 505 </span>
<span>115/505 = Δ(BA)/Δt = 23/101 </span>
<span>When the top of the coil rotates to the bottom (1/2 half cycle) BA changes from max to min and when the bottom rotates back to the top BA changes from min to max. So Δ(BA) is twice per cycle </span>
<span>So 2*101Δ(BA)=23Δt and Δt = 1/f </span>
<span>202*2.0064e-2/23 =Δt = 1/f => f =5.675Hz</span>
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Hey there! I will give the following steps, if you have any questions feel free to ask me in the comments below.

So this is the Formula: Power = Work / Time.

<u>Step 1:</u><em><u> Find the Formula</u></em>

P = W / T

<em><u> </u></em>

<u>Step 2: </u><u><em>Make W the subject of the equation.</em></u>

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<u>Step 3:</u><u> </u><u><em>Given.</em></u>

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<u>Step 4:</u><u><em> Substitute these values into equation 2 .</em></u>

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<u>Step 5:</u><u> </u><u><em>Simplify.</em></u>

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~I hope I helped you! :)~

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