The probability that a randomly selected professor is female and feels "About Right" is 0.40
The distribution table :
____About right _ Oweight _ Uweight __ Total
Female _ 80 _____ 39 ______ 3 _______ 122
Male ___ 52 _____ 10 ______ 16 _______ 88
Total ___ 132 ____ 49 ______ 19 _______ 200
Oweight = Overweight
Uweight = Underweight
Recall :
Probability = required outcome / Total possible outcomes
Probability that a selected professor is female and feels 'About right' :
Required outcome = number of female professors who feels 'About right' = 80
Total number of professors = 200
Hence,
P(Female and 'About right') = 80/200 = 0.40
Learn more : brainly.com/question/11234923
5y - 2x + 1 = 0.
5y = 2x-1.
y = 2/5 x - 2/5
this tells us that tan(theta) = 2/5
sin(theta)/sqrt(1-sin^2(theta)) = 2/5
x/sqrt(1-x^2)=2/5
x^2/(1-x^2)=4/25
25x^2=4-4x^2
29x^2=4
x^2=4/29
x = -2/sqrt(29) because quadrant III
cos(x) = sqrt(1-4/29) = -5/sqrt(29)
tan(theta)=2/5
cos(theta)=-5/sqrt(29)
sin(theta)=-2/sqrt(29)
cot(theta)=5/2
sec(theta)=-sqrt(29)/5
csc(theta)=-sqrt(29)/2
The domain is {-1.5, -1.2, -0.8, -0.5, 0, 1, 2} And the range is {0, -3}
