When we round a number the new rounded <span>number is </span>simpler but the value is kept close to what it was. The common method for rounding numbers is the following: we d<span><span>ecide which is the last digit to keep and l</span><span>eave this digit the same the same if the next digit is less than 5 or increase it by 1 if the next digit is bigger than 5.
</span></span>Because the next digit matter, it is not possible for a 5 digit number to be rounded to 6 digit number.
Answer:
D
Step-by-step explanation:
Because it is on the outside
By definition,
f'(x)=Lim h->0 (f(x+h)-f(x))/h
We are already given
f(x+h)-f(x)=<span>−6hx2−7hx−6h2x−7h2+2h3=h(-6x^2-7x-6hx-7h+2h^2)
divide by h
</span>(f(x+h)-f(x))/h =h(-6x^2-7x-6hx-7h+2h^2)/h=(-6x^2-7x-6hx-7h+2h^2)
Finally, take lim h->0
f'(x)=Lim h->0 (f(x+h)-f(x))/h=(-6x^2-7x-0-0+0)=-6x^2-7x
=>
f'(x)=-6x^2-7x
Consecutive numbers means that they are one after the other (i.e. 1, 2, 3 are consecutive numbers). The square of a number signifies the product of this number times itself (i.e. 2 times 2 = 4, so 4 is the square of 2). If these squares differ by 25, then when they are subtracted from one another, the difference will be 25:
12 x 12 = 144
13 x 13 = 169
169 - 144 = 25
