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miskamm [114]
3 years ago
9

Emissions from alpha decay require the least amount of shielding. Which best describes why the emissions from alpha decay are so

easily blocked compared to the emissions of other types of radioactive decay?
Alpha decay releases visible light, which has less energy than the light released during gamma decay.

Alpha decay releases particles that have less mass and charge than the particles released during beta decay.

Alpha decay releases particles that have less mass and charge than the particles released during gamma decay.

Alpha decay releases particles that have more mass and charge than the particles released during beta decay.
Physics
2 answers:
snow_lady [41]3 years ago
8 0

Answer:

D

Explanation:

i took the test :)

Crank3 years ago
4 0

Answer:

Alpha decay releases particles that have more mass and charge than the particles released during beta decay.

Explanation:

In the alpha decay, an alpha particle is emitted. An alpha particle is a nucleus of helium, consisting of two protons and two neutrons. The particle emitted in the beta decay is instead an electron: therefore, the alpha particle has more mass and more charge than a beta particle. For this reason, alpha particles are much more ionising than electrons, so they release much more energy per unit distance than beta particles, and so they lose all their energy much faster than beta particles. This is why alpha particles can be easily blocked even by a thin piece of paper, while beta particles are able to pass through.

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Match these items.
Nitella [24]

Explanation :

(1) Involuntary muscles are the muscles that are not controlled by our will.

(2) Tendons are the connective tissues that join the muscle to bones. Tendons are tissues that have fibers.

(3) Cardiac muscle is also involuntary muscles. For example heart muscle. It shows contraction and relaxation throughout life.

(4) Voluntary muscle is the muscles that are not controlled by our will.  

(5) Biceps are the arm muscles.

Hence, this the required explanation as per options.

4 0
3 years ago
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svlad2 [7]
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3 years ago
Read 2 more answers
In a ballistics test, a 24 g bullet traveling horizontally at 1200 m/s goes through a 31-cm-thick 320 kg stationary target and e
Zanzabum

Answer:

The  velocity is  v_t  =  0.02175 \  m/s

Explanation:

From the question we are told that

   The  mass of the bullet is  m_b  =  0.024 \  kg

    The initial speed of the bullet is  u_b  =  1200 \  m/s

   The mass of the target is  m_t  =  320 \  kg

    The  initial velocity of target is  u_t  =  0  \ m/s

    The  final velocity of the bullet is  is  v_b  =  910 \  m/s

   

Generally according to the law of momentum conservation we have that

      m_b *  u_b  +  m_t *  u_t  =  m_b *  v_b  +  m_t  *  v_t

=>   0.024  *  1200  +  320 *  0  =  0.024 *  910   +  320  *  v_t

=>    v_t  =  0.02175 \  m/s

3 0
4 years ago
If a football player does 39000 J of work, how much power does the football player exert in 5 minutes
Drupady [299]

Answer:

Power = 130 watt

Explanation:

Power is described as the ability to do work, it is also defined as the amount of work in Joules done in a given time in seconds. Mathematically, it is represented as:

power = \frac{work (J)}{Time (s)}

In this example, power is calculated as follows:

Work = 39000 J

Time = 5 minutes

converting the time from minutes to seconds:

1 minute = 60 seconds

∴ 5 minutes = 60 × 5 = 300 seconds

\therefore power = \frac{39000}{300} \\power = 130 watt

N:B the unit for power can also be represented as Joules/seconds or J/s or JS⁻¹

6 0
3 years ago
A block slides down a frictionless inclined ramp. If the ramp angle is 17.0° and its length is find the speed of the block as it
SashulF [63]

Answer:

2.4\sqrt{L} where L is the length of the ramp

Explanation:

Let L (m) be the length of the ramp, and g = 9.81 m/s2 be the gravitational acceleration acting downward. This g vector can be split into 2 components: parallel and perpendicular to the ramp.

The parallel component would have a magnitude of

gsin\theta = 9.81 sin17^o = 2.87 m/s^2

We can use the following equation of motion to find out the final velocity of the book after sliding L m:

v^2 - v_0^2 = 2a\Delta s

where v m/s is the final velocity, v_0 = 0m/s is the initial velocity when it starts from rest, a = 2.87 m/s2 is the acceleration, and \Delta s = L is the distance traveled:

v^2 - 0 = 2*2.87*L

v = \sqrt{5.74L} = 2.4\sqrt{L}

6 0
3 years ago
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