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3 years ago

Burl and Paul have a total weight of 992 N. The tensions in the ropes that

Physics

1 answer:

exis [7]3 years ago

6 0

Answer:

1670 N

Explanation:

The weight of ropes is negligible hence considering that Burl and Paul have a total weight of 992 N while the total weight of the scaffold while they are in it is equivalent to 2662 N then to get the weight if scaffold we have to deduct the the weight of Burl and Paul from the total weight.

Therefore, scaffold will be 2662-992= 1670 N

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Ilia_Sergeevich [38]

Answer:

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Explanation:

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2 years ago

Pick an activity you enjoy, such as running or riding a scooter, and describe how newton's laws apply to that activity.

deff fn [24]

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3 years ago

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Say you want to make a sling by swinging a mass M of 2.3 kg in a horizontal circle of radius 0.034 m, using a string of length 0

ycow [4]

Answer:

T = 764.41 N

Explanation:

In this case the tension of the string is determined by the centripetal force. The formula to calculate the centripetal force is given by:

$F_c=m\frac{v^2}{r}$ (1)

m: mass object = 2.3 kg

r: radius of the circular orbit = 0.034 m

v: tangential speed of the object

However, it is necessary to calculate the velocity v first. To find v you use the formula for the kinetic energy:

$K=\frac{1}{2}mv^2$

You have the value of the kinetic energy (13.0 J), then, you replace the values of K and m, and solve for v^2:

$v^2=\frac{2K}{m}=\frac{2(13.0J)}{2.3kg}=11.3\frac{m^2}{s^2}$

you replace this value of v in the equation (1). Also, you replace the values of r and m:

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hence, the tension in the string must be T = Fc = 764.41 N

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2 years ago

Freight trains can produce only relatively small acceleration and decelerations. (a) what is the final velocity (in m/s) of a fr

m_a_m_a [10]

(a) We will use the equation v = u + at
Initial velocity u = 5.00 m/s
Acceleration a = 0.0600 m/s²
time = 8 min = 8 x 60 = 480 s
Final velocity
= u + at
= 5.00 + 0.0600(480)
= 33.8 m/s

The final velocity is 33.8 m/s

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2 years ago

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if the net force of 15 N is exerted on an encyclopedia to cause it to accelerate at a rate of 5 m/s2. what is the mass of the en

Katarina [22]

Answer:

3 kg

Explanation:

F = ma

(15) = m(5)

m = 3 kg

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2 years ago