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UNO [17]
3 years ago
6

A force of 15 newtons is applied to both Object A with a mass of 25 kilograms and Object B with a mass of 50 kilograms. What is

true about the
acceleration of Object A and Object B?
ОА.
Acceleration of Object A is four times that of the acceleration of Object B.
Acceleration of Object A is the same as the acceleration of Object B.
OB.
OC.
Acceleration of Object Ais half the acceleration of Object B.
OD
Acceleration of Object A is twice that of the acceleration of Object B.
Physics
1 answer:
love history [14]3 years ago
3 0

acceleration of object ais help the acceleration of an object b OD

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If the maximum tension in the simulation is 10.0 N, what is the linear mass density (m/L) of the string
vovikov84 [41]

Complete Question

The speed of a transverse wave on a string of length L and mass m under T is given by the formula

     v=\sqrt{\frac{T}{(m/l)}}

If the maximum tension in the simulation is 10.0 N, what is the linear mass density (m/L) of the string

Answer:

(m/l)=\frac{10}{V^2}

Explanation:

From the question we are told that

Speed of a transverse wave given by

v=\sqrt{\frac{T}{(m/l)}}

Maximum Tension is T=10.0N

Generally making (m/l) subject from the equation mathematically we have

v=\sqrt{\frac{T}{(m/l)}}

v^2=\frac{T}{(m/l)}

(m/l)=\frac{T}{V^2}

(m/l)=\frac{10}{V^2}

Therefore the Linear mass in terms of Velocity is given by

(m/l)=\frac{10}{V^2}

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3 years ago
A 23.3-kg mass is attached to one end of a horizontal spring, with the other end of the spring fixed to a wall. The mass is pull
sdas [7]

In spring mass system we know that angular frequency is given as

\omega = 2\pi f

f = 8.38 Hz

\omega = 2\pi(8.38)

\omega = 52.65  rad/s

now we know that speed of SHM at its extreme position is given by

v = A\omega

here we know that

A = 17.5 cm

v = 0.175 (52.65)

v = 9.21 m/s

so maximum speed is 9.21 m/s

7 0
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Please help this is physics!!!
larisa [96]
I’m pretty sure u have it right
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SOMEONE HELP ME PLSS​
lara31 [8.8K]
1. 2500/60 joules/sec
2. 2,500Nm
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