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4 years ago

Charges cannot flow without:

Physics

2 answers:

9966 [12]4 years ago

5 0

Voltage is necessary for charge to flow

lakkis [162]4 years ago

5 0

Answer:

Voltage

Explanation:

Charges cannot flow without voltage which is also known as electromotive force. The electromotive force is known to be the driving force for current in an electric circuit. This emf or battery is the source voltage that has both positive and negative terminals. Current flows from out from the positive terminal of the battery. This means that the arrangement of the polarity of the battery determines the direction of flow of the electric current through an electric circuit. The flow of current in a DC circuit is in one direction i.e either clockwise or anticlockwise.

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Explain how the first three steps of scientific inquiry are related.

Mademuasel [1]

The first three steps in scientific inquiry are related in that they are all equivalent to being on a fact finding mission. The three steps are to find or develop the question that must be answered, to study all related academic literature on the subject, and then to make a guess as to what the answer is.
I hoped I helped!

4 0

3 years ago

Read 2 more answers

If the frequency of oscillation of the wave emitted by an fm radio station is 92.4 mhz, determine the wave's period of vibration

lapo4ka [179]

The basic relationship between the frequency of a wave and its period is
$f= \frac{1}{T}$
where f is the frequency and T the period of vibration.

In our problem, the frequency is
$f=92.4 MHz = 92.4 \cdot 10^6 Hz$
so, by re-arranging the previous formula, we can find the period of the wave:
$T= \frac{1}{f}= \frac{1}{92.4 \cdot 10^6 Hz}=1.1 \cdot 10^{-8} s$

3 0

3 years ago

You have 10 ohm and a 100 ohm resistor in parallel. You place this equivalent resistance in series with an LED, which is rated t

Nataly [62]

Answer:

Approximately $\rm 2.0\; V$ .

Approximately $\rm 30 \; mA$ . (assumption: the LED here is an Ohmic resistor.)

Explanation:

The two resistors here $R_1= 10\; \Omega$ and $R_2= 100\; \Omega$ are connected in parallel. Their effective resistance would be equal to

$\displaystyle \frac{1}{\dfrac{1}{R_1} + \dfrac{1}{R_2}} = \frac{1}{\dfrac{1}{10} + \dfrac{1}{100}} = \frac{10}{11} \; \Omega$ .

The current in a serial circuit is supposed to be the same everywhere. In this case, the current through the LED should be $20\; \rm mA = 0.020\; \rm A$ . That should also be the current through the effective $\displaystyle \rm \frac{10}{11} \; \Omega$ resistor. Make sure all values are in standard units. The voltage drop across that resistor would be

$V = I \cdot R = 0.020 \times \dfrac{10}{11} \approx 0.182\; \rm V$ .

The voltage drop across the entire circuit would equal to

the voltage drop across the resistors, plus
the voltage drop across the LED.

In this case, that value would be equal to $1.83 + 0.182 \approx 2.0\; \rm V$ . That's the voltage that needs to be supplied to the circuit to achieve a current of $20\; \rm mA$ through the LED.

Assuming that the LED is an Ohmic resistor. In other words, assume that its resistance is the same for all currents. Calculate its resistance:

$\displaystyle R(\text{LED}) = \frac{V(\text{LED})}{I(\text{LED})}= \frac{1.83}{0.020} \approx 91.5\; \Omega$ .

The resistance of a serial circuit is equal to the resistance of its parts. In this case,

$\displaystyle R = R(\text{LED}) + R(\text{Resistors}) = 91.5 + \frac{10}{11} \approx 100\; \Omega$ .

Again, the current in a serial circuit is the same in all appliances.

$\displaystyle I = \frac{V}{R} = \frac{3}{100} \approx 0.030\; \rm A = 30\; mA$ .

7 0

3 years ago

Which option is a force: A. velocity B. acceleration C. mass D. weight

ehidna [41]

Answer:

Explanation:

Weight and force have same derived units

8 0

3 years ago

If total (PE + KE) is conserved:

lorasvet [3.4K]

Yes, According to law of conservation of energy the total energy of any system remains conserved (same).

Example.

If a body is placed at some height it possesses some potential energy.

As P.E =mgh

When this body is starting moving downwards its height becomes decreases so P.E decreases but at the same time it is moving I.e having some velocity. K.E =1/2(m)(v^2).

Hence here P.E decreases but K.E increases at the same time. So total energy is conserved.

6 0

4 years ago