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Juli2301 [7.4K]
3 years ago
8

A perpendicular force is applied to a certain area and produces a pressure P. If the

Physics
1 answer:
Furkat [3]3 years ago
4 0

Answer:

p/2

Explanation:

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A current of 0. 82 a flows through a light bulb. how much charge passes through the light bulb during 94 s?
gladu [14]

A current of 0. 82A flows through a light bulb. The charge passed through the light bulb during 94 s is 77.08C

The amount of charge flown for a given period of time determines the current passed through a bulb or electrical body.

The relation between the charge, current and time is given as:

Q = I × t

where, Q is the charge flown through bulb

I is the current passed through bulb

t is the time for which charge passes through bulb

Given,

I = 0.82A

t = 94s

Q = ?

Substituting the values in the above formula:

Q = I × t

Q = 0.82 × 94

Q = 77.08C

Hence, The charge passed through the light bulb during 94 s is 77.08C

Learn more about Current here, brainly.com/question/2264542

#SPJ4

4 0
1 year ago
30 Points 4 correct answer!!! ^u^
lakkis [162]
Lithium has an atomic number of 3 so right away all the answer choices are eliminated except A., and oxygen does have 8 neutrons, boron 5 electrons, and neon a mass of 20
3 0
3 years ago
Read 2 more answers
The image shows a roller coaster.
mariarad [96]
I believe the answer is c but I’m not 100% sure
8 0
3 years ago
A marble rolling at a speed of 2 meters per second falls off the end of a 1-meter high table. How long will the marble be in the
irga5000 [103]

<span>t^2 = 1/4.9 </span>
<span>t = 0.45 sec 
 answer:</span><span>1 - 4.9t^2 = 0 </span>
8 0
3 years ago
A speed skater moving across frictionless ice at 9.2 m/s hits a 5.0 m wide patch of rough ice. She slows steadily, then continue
enot [183]

Answer:

a = -5.10 m/s^2

her acceleration on the rough ice is -5.10 m/s^2

Explanation:

The distance travelled on the rough ice is equal to the width of the rough ice.

distance d = 5.0 m

Initial speed u = 9.2 m/s

Final speed v = 5.8 m/s

The time taken to move through the rough ice can be calculated using the equation of motion;

d = 0.5(u+v)t

time t = 2d/(u+v)

Substituting the given values;

t = 2(5)/(9.2+5.8)

t = 2/3 = 0.66667 second

The acceleration is the change in velocity per unit time;

acceleration a = ∆v/t

a = (v-u)/t

Substituting the values;

a = (5.8-9.2)/0.66667

a = -5.099974500127

a = -5.10 m/s^2

her acceleration on the rough ice is -5.10 m/s^2

7 0
3 years ago
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