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3 years ago

A perpendicular force is applied to a certain area and produces a pressure P. If the

Physics

1 answer:

Furkat [3]3 years ago

4 0

Answer:

p/2

Explanation:

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4 Points

lbvjy [14]

Answer:

Impulse = 322.5[kg*m/s], the answer is D

Explanation:

This method it is based on the principle of momentum and the amount of movement; and used to solve problems involving strength, mass, speed and time.

If units of the SI are used, the magnitude of the impulse of a force is expressed in N * s. however, when remembering the definition of the newton.

$N*S=(kg*m/s^{2} )*s = kg*m/s$

Now replacing the values on the following equation that express the definition of impulse

$Impulse = Force * Time\\\\Impulse = 215 * 1.5 = 322.5 [kg*m/s]$

4 0

3 years ago

Read 2 more answers

The center of gravity method is used to ________ travel time

icang [17]

Answer:

minimizes

Explanation:

The center of gravity method consists of an algorithm for the location of an installation considering existing ones. This is a very simple technique and is usually used to determine the location of intermediate warehouses and distribution points taking into account the distances that separate them and the contribution (in terms of utility, production or capacity) of each installation.

This location method takes into account three transport factors:

Ci: Transportation cost per unit

Vi: Volume transported from unit i

di: Distance traveled in the transport of the unit i

The primary objective of this method is to find the best location of a given installation of a company with respect to the other elements that make it up, to guarantee the minimum possible time and the minimum Total Transportation Cost.

4 0

3 years ago

How can physicists use Newton’s laws of motion and universal gravitation to predict objects’ motion?

koban [17]

Answer:

Newtons law of universal gravitation is the phenomena in which Newton said that every particle in environment will attract other particles in the space.

Explanation:

Newton law of motion and gravitation attract forcefully which is direct proportional to the masses of the particles and inversely proportional to the square of the distances between the centers. Other physicist used Newtons law in research related to motion or to find out the distance between earth and sun. Because this law is about the mass of the objects. When the mas of an object is doubled, the force between the objects get too doubled. When the mass of the two objects is doubled the gravitational pull between these two objects gets doubled. Sir Isaac Newton first gave this law when see fall down an apple from tree.

Formula is : F = G Mm/r2 Here G is gravitational pull that is constant.

5 0

4 years ago

What is the effective resistance r of the two-resistor system? express the effective resistance in terms of r1 and r2?

Alekssandra [29.7K]

As per the question, the resistor system contains two resistors.

The two resistors are denoted as $r_{1}\ and\ r_{2}\ respectively$

We are asked to calculate the effective resistance in terms of $r_{1}\ and\ r_{2}\ respectively$

The two resistors can be connected in two ways.

CASE-1: Let the resistors are connected in series.

When the resistors are connected in series, the effective resistance is the algebraic sum of the individual resistors.

Hence, the effective resistance $r= r_{1} +r_{2}$ [ans]

CASE-2: Let the resistors are connected in parallel.

The effective resistance is calculated as follows-

$\frac{1}{r}= \frac{1}{ r_{1}}+ \frac{1}{r_{2}}$

$=\frac{r_{1}+ r_{2}} {r_{1} r_{2}}$

⇒ $r =\frac{r_{1} r_{2}} { r_{1} +r_{2}}$ [ans]

4 0

4 years ago

Two particles with masses 2m and 9m are moving toward each other along the x axis with the same initial speeds vi. Particle 2m i

s2008m [1.1K]

Answer:

The final speed for the mass 2m is $v_{2y}=-1,51\ v_{i}$ and the final speed for the mass 9m is $v_{1f} =0,85\ v_{i}$ .

The angle at which the particle 9m is scattered is $\theta = -66,68^{o}$ with respect to the - y axis.

Explanation:

In an elastic collision the total linear momentum and the total kinetic energy is conserved.

<u>Conservation of linear momentum:</u>

Because the linear momentum is a vector quantity we consider the conservation of the components of momentum in the x and y axis.

The subindex 1 will refer to the particle 9m and the subindex 2 will refer to the particle 2m

$\vec{p}=m\vec{v}$

$p_{xi} =p_{xf}$

In the x axis before the collision we have

$p_{xi}=9m\ v_{i} - 2m\ v_{i}$

and after the collision we have that

$p_{xf} =9m\ v_{1x}$

In the y axis before the collision $p_{yi} =0$

after the collision we have that

$p_{yf} =9m\ v_{1y} - 2m\ v_{2y}$

$p_{xi} =p_{xf} \\7m\ v_{i} =9m\ v_{1x}\Rightarrow v_{1x} =\frac{7}{9}\ v_{i}$

then

$p_{yi} =p_{yf} \\0=9m\ v_{1y} -2m\ v_{2y} \\v_{1y}=\frac{2}{9} \ v_{2y}$

<u>Conservation of kinetic energy:</u>

$\frac{1}{2}\ 9m\ v_{i} ^{2} +\frac{1}{2}\ 2m\ v_{i} ^{2}=\frac{1}{2}\ 9m\ v_{1f} ^{2} +\frac{1}{2}\ 2m\ v_{2f} ^{2}$

$\frac{11}{2}\ m\ v_{i} ^{2} =\frac{1}{2} \ 9m\ [(\frac{7}{9}) ^{2}\ v_{i} ^{2}+ (\frac{2}{9}) ^{2}\ v_{2y} ^{2}]+ m\ v_{2y} ^{2}$

Putting in one side of the equation each speed we get

$\frac{25}{9}\ m\ v_{i} ^{2} =\frac{11}{9}\ m\ v_{2y} ^{2}\\v_{2y} =-1,51\ v_{i}$

We know that the particle 2m travels in the -y axis because it was stated in the question.

Now we can get the y component of the speed of the 9m particle:

$v_{1y} =\frac{2}{9}\ v_{2y} \\v_{1y} =-0,335\ v_{i}$

the magnitude of the final speed of the particle 9m is

$v_{1f} =\sqrt{v_{1x} ^{2}+v_{1y} ^{2} }$

$v_{1f} =\sqrt{(\frac{7}{9}) ^{2}\ v_{i} ^{2}+(-0,335)^{2}\ v_{i} ^{2} }\Rightarrow \ v_{1f} =0,85\ v_{i}$

The tangent that the speed of the particle 9m makes with the -y axis is

$tan(\theta)=\frac{v_{1x} }{v_{1y}} =-2,321 \Rightarrow\theta=-66,68^{o}$

As a vector the speed of the particle 9m is:

$\vec{v_{1f} }=\frac{7}{9} v_{i} \hat{x}-0,335\ v_{i}\ \hat{y}$

As a vector the speed of the particle 2m is:

$\vec{v_{2f} }=-1,51\ v_{i}\ \hat{y}$

8 0

3 years ago