Explanation:
V = 3 cm/s = 0.03 m/s. BY THE FORmULA OF K.E. K.E = 1/2 mV^2. 300 =1/2 m (0.03)^2. m = 300 x 2/0.0009.
Answer:
A= 203 KJ
B= 54 Kg
Explanation:
The initial specific volumes and internal energies are obtained from A-12 for a given pressure and state. The enthalpy of the refrigerant in the supply line is determined using the saturated liquid approximation for the given temperature with data from A-11. The mass that has entered the tank is:
Δm = m₂ – m₁
= V(1/α₂ – 1/α₁)
= 0.05 (1/0.0008935 – 1/ 0.025645)Kg
= 54Kg
The heat transfer is obtained from the energy balance:
ΔU= +
m₂u₂ – m₁u₂ = +
= m₂u₂ – m₁u₁ –
= V/α₂u₂ - V/α₁u₁ –
=(0.05/0.0008935 . 116.72 – 0.05/0.025645 . 246.82 – 54.108.28) Kj
= 203 KJ
60 ° is the angle between W- direction and the run direction.
You need the angle betwee S-direction and the run direction. This is 90° - 60° = 30 °.
By geometry you can trace a right triangle, where the S-component is the adyacent side and the run is the hypotenuse.
Then cos 30° = adyacent side / hypotenuse = S-component / run
Then S-component = run * cos 30° = 5.0 km * 0.866 = 4.3 km
Answer: 4.3 km
The magnitude of the force exerted on this object is 1.2 Newton.
<u>Given the following data:</u>
- Change in momentum = 12 Kgm/s.
<h3>What is impulse?</h3>
In Science, the impulse that is experienced by an object is always equal to the change in momentum of the object, due to the force acting on an object.
Mathematically, impulse is given by this formula:
Substituting the given parameters into the formula, we have:
Force = 1.2 Newton.
Read more on force here: brainly.com/question/16750406
(a) The angular speed of the system at the instant the beads reach the end of the rod is 9.26 rad/s.
(b) The angular speed of the rod after the after the beads fly off the rod's ends is 25.71 rad/s.
<h3>Moment of inertia through the center of the rod</h3>
I = ¹/₁₂ML²
I = ¹/₁₂ (0.1)(0.5)²
I = 0.0021 kgm²
For the beads, I = 2Mr² = 2(0.03 x 0.1²) = 0.0006 kgm²
Total initial moment of inertia, Ii = 0.0021 kgm² + 0.0006 kgm²
I(i)= 0.0027 kgm²
When the beads reach the end, I = 2Mr² = 2(0.03)(0.25)² = 0.00373 kgm²
Total final moment of inertia, I(f) = 0.0021 kgm² + 0.00373 kgm²
I(f) = 0.00583 kgm²
<h3>Speed of the system</h3>
The speed of the system at the moment the beads reach the end of the rod is calculated as follows;
<h3>Speed of the rod when the beads fly off</h3>
Learn more about moment of inertia of rods here: brainly.com/question/3406242