1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AlladinOne [14]
3 years ago
12

What is the steric number of H2O2?

Chemistry
1 answer:
chubhunter [2.5K]3 years ago
8 0

Answer: 1(2)+6(2)=14

Explanation:

Not sure, but maybe.

You might be interested in
List a possible set of four quantum numbers (n,l,ml,ms) in order, for the highest energy electron in gallium?
Elena-2011 [213]
Gallum: Z = 31

electron configuration: [Ar] 4s^2 3d10 4s2 4p1

Highest energy electron: 4p1

Quantum numbers:

n = 4, because it is the shell number
l = 1, it corresponds to type p orbital 
ml = may be -1, or 0, or +1, depending on space orientation, they correspond to px, py, pz
ms = may be -1/2 or +1/2, this is the spin number. 
7 0
3 years ago
In a desert, soil containing a mixture of sand and small rocks is exposed to wind erosion. Over time, how would the land surface
amid [387]
Sand dunes would be created due to the mixture falling on each other
x
3 0
3 years ago
Read 2 more answers
When an acid reacts with a strong base which product always forms
patriot [66]

Answer:طيزي

Explanation:

4 0
3 years ago
What mass of H₂ is needed to react with 8.75 g of O₂ according to the following equation: O2(g) + H2(g) → H₂O(g)?
FromTheMoon [43]

Explanation:

For reacting with 8.75 grams of oxygen, 1.08 grams of hydrogen is required.

The given balanced equation has been:

\rm O_2\;+\;2\;H_2\;\rightarrow\;H_2OO2+2H2→H2O

From the equation, 1 mole of oxygen reacts with 2 mole of hydrogen to give 1 mole of water.

The mass of oxygen has been: 8.75 g,

Moles = \rm \dfrac{weight}{molecular\;weight}molecularweightweight

Moles of oxygen = \rm \dfrac{8.75}{32}328.75

Moles of oxygen = 0.27 mol

Since,

1 mole Oxygen = 2 mole hydrogen

0.21 mol oxygen = 0.54 mol hydrogen

Mass of hydrogen = moles \times× molecular weight

Mass of hydrogen = 0.54 \times× 2

Mass of hydrogen = 1.08 grams.

Thus, for reacting with 8.75 grams of oxygen, 1.08 grams of hydrogen is required.

6 0
2 years ago
The value of ka for nitrous acid (hno2) at 25 ∘c is 4.5×10−4. what is the value of δg at 25 ∘c when [h+] = 5.9×10−2m , [no2-] =
LuckyWell [14K]
To get the value of ΔG we need to get first the value of ΔG°:

when ΔG° = - R*T*㏑K

when R is constant in KJ = 0.00831 KJ

T is the temperature in Kelvin = 25+273 = 298 K

and K is the equilibrium constant = 4.5 x 10^-4

so by substitution:

∴ ΔG° = - 0.00831 * 298 K * ㏑4.5 x 10^-4

        = -19 KJ

then, we can now get the value of ΔG when:

ΔG = ΔG° - RT*㏑[HNO2]/[H+][NO2]

when ΔG° = -19 KJ

and R is constant in KJ = 0.00831 

and T is the temperature in Kelvin = 298 K

and [HNO2] = 0.21 m & [H+] = 5.9 x 10^-2 & [NO2-] = 6.3 x 10^-4 m  

so, by substitution:

ΔG = -19 KJ - 0.00831 * 298K* ㏑(0.21/5.9x10^-2*6.3 x10^-4 )

       = -40

     
8 0
3 years ago
Other questions:
  • If a sodium atom looses an electron to form an ion what is its charge?
    10·2 answers
  • Wind happens when
    10·2 answers
  • When comparing the two elements P and I , the element with the higher first ionization energy is PP When comparing the two eleme
    10·1 answer
  • 30 POINTS
    9·2 answers
  • When looking at the effect of temperature on sucrase activity, the ph was set to which number? why was this number chosen?
    9·1 answer
  • Ok so N2+O2=2NO and my delta h is 180.5 kJ I need to know. If I react 10 g of nitrous gas with excess oxygen how many grams of N
    10·1 answer
  • Please Answer fast
    5·2 answers
  • How many atoms of Neon are in 65.0 L of Neon gas?
    8·2 answers
  • How many moles of HNO₃ will be produced from the reaction of 37.0 g of NO₂ with excess water in the following chemical reaction?
    13·1 answer
  • Help me pls I will mark you as brain
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!