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3 years ago

What are some facts about light?

Chemistry

1 answer:

dybincka [34]3 years ago

3 0

Answer:

A neon lamp was switched on during the Great Depression and continued to burn until it was discovered some 77 years later. The electricity bill came up to a whopping $17 000!

Explanation:

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Aluminum oxide (Al2O3) occurs in nature as a mineral called corundum, which is noted for its hardness and resis- tance to attack

Neko [114]

Answer:

7.03×10²³ atoms of Al

Explanation:

Corundum density = 3.97g/cm³

Corundum = Al₂O₃. Then, you have 2 moles of Al and 3 moles of O in 1 mol of the compound.

Let's determine the mass of corundum, by density

Corundum density = Corundum mass / Corundum volume

3.97 g/cm³ = Corundum mass / 15cm³

3.97 g/cm³ . 15cm³ = Corundum mass →59.55 g

Now, let's find out how many moles are in that mass of corundum

1 mol of Al₂O₃ weighs 101.96 g/mol

Then, 101.96 grams of oxide have 2 moles of Al

59.55 g of oxide, will have (59.55 .2)/101.96 = 1.17 moles

Now, we can know the quantity of atoms, by this rule of three

1 mol has NA atoms (6.02×10²³)

1.17 moles will have (1.17 . NA) = 7.03×10²³ atoms of Al

5 0

3 years ago

You adjust the temperature so that a sound wave travels more quickly through the air. You increase the temperature from 30°C to

olasank [31]

<h3><u>Answer;</u></h3>

C. 352.6 m/s

<h3><u>Explanation;</u></h3>

Velocity of sound is dependent on temperature. An increase in temperature, increases the velocity of sound.

To calculate the velocity of the sound wave, we use this formula:

V = 331 + [0.6*T]; Where V is the velocity and T represents temperature.

When the temperature is 36 degree Celsius, we have

V = 331 + [0.6 * 36]

V = 331 + 21.6 = 352.6

Therefore,

V = 352.6 m/s.

4 0

3 years ago

Two waves were analyzed with some high-tech instrumentation. The first wave was found to have a wavelength of 3 x 10 m and the s

a_sh-v [17]

Explanation:

The first wave was found to have a wavelength of 3 x 10⁵ m and the second wave had a wavelength of 3 x 10⁴ m

We need to find which wave have a higher frequency.

The relation between frequency and wavelength is given by :

$c=f\lambda$

Let f₁ and f₂ be the frequency of wave 1 and wave 2.

$f_1=\dfrac{c}{\lambda_1}\\\\f_1=\dfrac{3\times 10^8}{3\times 10^5}\\\\=1000\ Hz$

And

$f_2=\dfrac{c}{\lambda_2}\\\\f_2=\dfrac{3\times 10^8}{3\times 10^4}\\\\=10000\ Hz$

Hence, the wave having less wavelength will have higher frequency. The wave having wavelength 3 x 10⁴ m will have higher frequency.

8 0

3 years ago

How are evaporation and condensation related?

natulia [17]

Both evaporation and condensation are in the water cycle. evaporation is when water changes from liquid to gas meanwhile condensation is when water vapor cools and goes from gas to liquid.

8 0

4 years ago

Which of the following is true for the actual yield of a reaction?

ludmilkaskok [199]

Answer:

It is always less than the theoretical yield

Explanation:

For many chemical reactions, the actual yield is usually less than the theoretical yield. This is due to possible loss in the process or inefficiency of the chemical reaction.

4 0

3 years ago

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