All categories

3 years ago

Which expression is greater than -|-9.02|?

Mathematics

2 answers:

viktelen [127]3 years ago

6 0

Step-by-step explanation:

snow_tiger [21]3 years ago

6 0

The second one because the absolute value is 9.02

You might be interested in

The radius of a circle is 3 5/12 inches <br> What is the diameter of the circle?

nirvana33 [79]

Answer:

6 5/6

Step-by-step explanation:

diameter is radius multiplied by 2

* means multiplied by

3 5/12 = 41/12

41/12 * 2 = 82/12 = 6 5/6

8 0

2 years ago

Read 2 more answers

Translate the phrase into a numerical expression of One hundred divided by the quantity three times five

dimulka [17.4K]

$\frac{100}{3*5}$

4 0

4 years ago

What is the measure of DG?

Masja [62]

Answer:

170

Step-by-step explanation:

7 0

3 years ago

Find the distance between the points with coordinates (-26,0) and (95, 0).

mote1985 [20]

Answer:

Step-by-step explanation:

Distance between two points is the slope .

Slope =change in y/change in x

Given (-26,0) and (95,0)

x1 = -26

y1 = 0

x2 = 95

y2 = 0

Slope = y2 - y1 / x2 - x1

0-0/95-(-26)

0-0/95+26

0/121

4 0

4 years ago

Find the length of the curve. R(t) = cos(8t) i + sin(8t) j + 8 ln cos t k, 0 ≤ t ≤ π/4

arsen [322]

we are given

$R(t)=cos(8t)i+sin(8t)j+8ln(cos(t))k$

now, we can find x , y and z components

$x=cos(8t),y=sin(8t),z=8ln(cos(t))$

Arc length calculation:

we can use formula

$L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt$

$x'=-8sin(8t),y=8cos(8t),z=-8tan(t)$

now, we can plug these values

$L=\int _0^{\frac{\pi }{4}}\sqrt{(-8sin(8t))^2+(8cos(8t))^2+(-8tan(t))^2} dt$

now, we can simplify it

$L=\int _0^{\frac{\pi }{4}}\sqrt{64+64tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{1+tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{sec^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8sec(t) dt$

now, we can solve integral

$\int \:8\sec \left(t\right)dt$

$=8\ln \left|\tan \left(t\right)+\sec \left(t\right)\right|$

now, we can plug bounds

and we get

$=8\ln \left(\sqrt{2}+1\right)-0$

so,

$L=8\ln \left(1+\sqrt{2}\right)$ ..............Answer

5 0

3 years ago