<img src="https://tex.z-dn.net/?f=%5Cint%5Climitsd%20%5Cfrac%7B1%7D%7Bcos%5E%7B6%7Dx%20%7D%20%5C%2C%20dx" id="TexFormula1" title

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2 years ago

="\int\limitsd \frac{1}{cos^{6}x } \, dx" alt="\int\limitsd \frac{1}{cos^{6}x } \, dx" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Brilliant_brown [7]2 years ago

6 0

Answer:

Nicole |2/22|19|Don't mess with me|r4rail |Blue|Salad|USA|Cool|Hero|255|20|64|11|3|3|599|0|1|1|3|1|52|19|108|42|0|114|114|2|2|50|50|160|48|112|6|0|113|143|0|0|0|84|0|22|22|18|18|0|0|0|0|55|0|10|10|7|0|0|93|38|0|0|0|17|17|0|255|1|1|0|1|1|1|0|0|1|1|2|8|1|1|2|2|1|1|19|1|1|0|0|27|15|2|0|1|0|18|12|2|1|0|0|0|0|0|1|3|2|20|0|-1|3|2|20|0|0|0|1|1|0|0|0|1|1|0|1|8|18|19|0|-1|9|18|19|0|0|-1|1|3|0|4|-1|1|1|0|14|4|3|2|0|-1|2|1|3|354|2|0|1|20|351|0|0|1|1|0|0|0|1|1|0|0|0|1|1|0|46|6|12|13|12|8|-2|18|17|0|25|35|2|2|28|0|0|0|1|1|0|0|12|17|16|351|1|3|1|13|20|18|0|0|1|1|1|1|0|1|1|0|0|1|1|0|1|1|1|1|1|1|1|1|1|1|1|1|1|1|1|1|1|1|0|0|1|1|0|1|0|0|0|1|1|0|8|3|3|0|0|0|0|0|30|-62|0|-4|0|1|4|1|3|0|18|0|6|0|0|0|0|0|C49067|8A624F|191919|27170F|191919|191919|3A1F17|191919|27170F|020202|191919|191919|020202|191919|00BDB7|3A1F17|0256C9|B15482|FFFFFF|020202|14002C|020202|FFFFFF|14002C|020202|FFFFFF|020202|FFFFFF|020202|01449F|020202|01449F|020202|020202|191919|020202|D4AE91|562D25|FFF0E7|C49067|020202|FF93BC|FFFFFF|020202|8AAEFF|FF8383|FFFFFF|BB9178|8C664F|FF8383|020202|FFFFFF|540000|020202|4D0119|DEECFF|020202|3A82FF|EBE0FF|020202|8AAEFF|0256C9|020202|8AAEFF|E0E1FF|020202|8ACEFF|020202|020202|FFFFFF|1003C2|020202|4638FF|FFFFFF|020025|00566B|FFFFFF|020025|00566B|020202|020202|8589FF|020202|020202|8589FF|8589FF|020202|3D3E62|8589FF|020202|3D3E62|8AAEFF|020025|3FC4FF|3A82FF|020025|8C3FFF|020202|020202|FFFFFF|020202|020202|FFFFFF|1604FC|020202|A487FF|1604FC|020202|A487FF|4638FF|020202|3A82FF|4638FF|020202|3A82FF|08016D|007591|0C0295|FFFFFF|14002C|FFFFFF|191919|020025|1003C2|3A027E|0093B6|1604FC|0C0295|0093B6|1604FC|FF3F3F|020202|FFC2C2|FFFAB6|020202|FFFFFF|9F0000|020202|FFFFFF|FF3F3F|020202|191919|FFFFFF|00232C|FFFFFF|FFFFFF|FFFFFF|FFFFFF|01449F|00132C|0256C9|6605D9|00132C|0256C9|00132C|020202|020202|FFFFFF|020202|FFFFFF|020202|020202|020202|020202|020202|020202

Step-by-step explanation:

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Write an equation in slope-intercept form for the following line:<br> (-14.1) and (13,-2)

vesna_86 [32]

Answer:

$y=-\frac{1}{9}x-\frac{5}{9}$

Step-by-step explanation:

$(-14,1)(13,-2)$

Use the slope-intercept formula:

$y=mx+b$

m is the slope and b is the y-intercept. Use the slope formula first:

$\frac{y_{2}-y_{1}}{x_{2}-x_{1}} =\frac{rise}{run}$

Rise over run is the change in the y-axis over the change in the x-axis. Plug in the coordinates:

$(-14(x_{1}),1(y_{1}))\\(13(x_{2}),-2(y_{2}))$

$\frac{-2-1}{13-(-14)}$

Simplify parentheses (two negatives makes a positive):

$\frac{-2-1}{13+14}$

Simplify:

$\frac{-3}{27} =-\frac{3}{27}=-\frac{1}{9}$

The slope is $-\frac{1}{9}$ . Insert into the equation:

$y=-\frac{1}{9}x +b$

Now, to find the y-intercept, take one of the points and substitute for the x and y values of the equation:

$(13,-2)\\-2=-\frac{1}{9} (13)+b$

Solve for b, the y-intercept. Simplify parentheses:

$-\frac{1}{9}*\frac{13}{1}=-\frac{13}{9}$

$-2=-\frac{13}{9} +b$

Add $-\frac{13}{9}$ to both sides:

$-2+\frac{13}{9}=-\frac{13}{9} +\frac{13}{9} +b\\\\-2+\frac{13}{9} =b$

Simplify:

$-\frac{2}{1} +\frac{13}{9}\\\\-\frac{18}{9}+\frac{13}{9}\\ \\b=-\frac{5}{9}$

The y-intercept is $-\frac{5}{9}$ . Insert this into the equation:

$y=-\frac{1}{9} x-\frac{5}{9}$

Finito.

8 0

3 years ago

1. Ms. Dawson’s call did a science experiment. The class started out with 650 bacteria cells. The growth rate predicted was 4.75

MatroZZZ [7]

The exponential function is y = 650(1.0475)ˣ

<h3>Exponential equation</h3>

A Exponential equation is in the form:

y = abˣ

where y, x are variables, b is the multiplier and a is the initial value.

Let y represent the bacteria population after x hours.

a = 650 bacteria

b = 100% + 4.75% = 1.0475

The exponential function is y = 650(1.0475)ˣ

After 33 hours:

y = 650(1.0475)³³ = 3006

Find out more on Exponential equation at: brainly.com/question/2456547

8 0

2 years ago

Help me plz this test is hard

kenny6666 [7]

Answer:

B I think

Step-by-step explanation:

7 0

2 years ago

A kite is flying 20 ft off the ground. Its line is pulled taut and casts a 15 ft - shadow. Find the length of the line. If neces

Kryger [21]

Answer:

The answer to your question is 25 ft

Step-by-step explanation:

Data

height = 20 ft

leg = 15 ft

length of the line = ?

To solve this problem use the Pythagorean theorem.

Height = short leg = b

leg = long leg = a

length of the line = hypotenuse = c

- Substitution

c² = (20)² + (15)²

-Simplification

c² = 400 + 225

c² = 625

-Result

c = $\sqrt{625}$

c = 25 ft

6 0

3 years ago

I need to solve×:5×10=2

PSYCHO15rus [73]

I hope this helps you

6 0

3 years ago