In a free body diagram for an object projected upwards;
- the acceleration due to gravity on the object is always directed downwards.
- the velocity of the object is always in the direction of the object's motion.
An object projected upwards is subjected to influence of acceleration due to gravity.
As the object accelerates upwards, its velocity decreases until the object reaches maximum height where its velocity becomes zero and as the object descends its velocity increases, which eventually becomes maximum before the object hits the ground.
To construct a free body diagram for this motion, we consider the following;
- the acceleration due to gravity on the object is always directed downwards
- the velocity of the object is always in the direction of the object's motion.
<u>For instance:</u>
upward motion for velocity ↑ downward motion for velocity ↓
↑ ↓
↑ ↓
acceleration due to gravity ↓
↓
↓
Learn more here: brainly.com/question/13235430
Answer:
The displacement of Sudhir is 0.781 km.
Explanation:
Given;
initial distance, d₁ = 0.4 km = 400 m, N60.0°W
final distance, d₂ = 0.5 km
Make a sketch of Sudhir motion to form a right angled triangle;
(Check image uploaded).
Apply cosine rule to determine d "displacement"
d² = 500² + 400² - (2 x 500 x 400 x cos 120)
d² = 410,000 - (400,000 x -0.5)
d² = 410,000 - (-200,000)
d² = 410,000 + 200,000
d² = 610,000
d = √610000
d = 781.03 m
d = 0.781 km
Therefore, the displacement of Sudhir is 0.781 km.
Answer:
θ = 4.716 10⁻⁶ rad
Explanation:
In order for the releases to be considered separate, they must meet the Rayleigh criterion that establishes that the maximum diffraction of one star must coincide with the first minimum of the diffraction pattern of the second star.
We use the diffraction equation for a slit
a sin θ = m λ
The minimum occurs at m = 1
sin θ = λ / a
Since the angles in these systems are very small, we can approximate the sine to its angle in radians
θ = λ / a
The telescope has a circular aperture whereby polar cords should be used, which introduces a constant number
θ = 1.22 λ / a
Let's calculate
θ = 1.22 518 10⁻⁹ / 13.4 10⁻²
θ = 4.716 10⁻⁶ rad
The answer should be C.
Ratio it has two radioactive isotopes is compared by overtime.
Hope it helped you.
-Charlie
The answer is the letter a
