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coldgirl [10]
4 years ago
8

A coin completes 18 spins in 12 seconds. The centripetal acceleration of the edge of the coin is 2.2 m/s2. The radius of the coi

n is m.
Physics
2 answers:
kompoz [17]4 years ago
4 0

Answer: 0.025 m or 2.5m

Explanation:

The number of spins given in 12 seconds = 18

So the number of spins in 1 second will be

= 18 / 12 = 1.5rps

The above result is the frequency because it is the number of spins in one second

Let f be frequency

f = 1.5 rps

Using centripetal acceleration given

Ca = 2.2 m/s^2

m is the radius of the given coin

Using the formula

Centripetal acceleration, = m x w^2

Knowing that w = 2πf

2.2 = m x ( 2 x 3.14 x 1.5) ^2

2.2 = m x 88.7364

m = 0.025 m

stellarik [79]4 years ago
3 0

Answer:

2.5 cm

Explanation:

Number of spins in 12 seconds = 18

Number of spins in 1 second = 18 / 12 = 1.5

Number of spins in one second is called frequency.

f = 1.5 rps

ac = 2.2 m/s^2

Let r be the radius of coin

Centripetal acceleration, ac = r x w^2

2.2 = r x ( 2 x 3.14 x 1.5) ^2

2.2 = r x 88.7364

r = 0.025 m = 2.5 cm

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Explanation:

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What are the magnitude and direction of the net force on the third spider (S3) when it is resting at the origin
Alex

Complete Question

The complete question is shown on the first uploaded image

Answer:

The  magnitude is  F_3 =0.62\ N

Explanation:

From the question we are told that

    The distance between the spiders is  a =0.59\ m

    The  charge on the S_1\ and\ S_3 is  q_{1}=q_{3}=q =+4.9\mu \ C

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