Answer:
k_2 = 7.815 * 10^-3 s^-1
Explanation:
Given:
- rate constant of reaction k_1 = 7.8 * 10^-3 s^-1 @ T_1 = 25 C
- rate constant of reaction k_2 = ? @ T_2 = 75 C
- The activation energy E_a = 33.6 KJ/mol
- Gas constant R = 8.314472 KJ / mol . K
Find:
- rate of reaction k_2 @ T_2 = 75 C
Solution:
- we will use a combined form of Arrhenius equations that relates rate constants k as function of E_a and temperatures as follows:
k_2 = k_1 * e ^ [(E_a / R) * ( 1 / T_1 - 1 / T_2 )
- Evaluate k_2 = 7.8 * 10^-3* e^[(33.6 / 8.314472)*(1/298 -1/348)
- Hence, k_2 = 7.815 * 10^-3 s^-1
In a high-mass, main-sequence star energy produces at a faster rate by using carbon in a process that fuses hydrogen to helium.
A high mass star produces energy by the fusion of hydrogen to helium.
But in this process, oxygen, carbon and nitrogen act as catalyst to accelerate the energy generation process.
Energy burn very quickly and at a faster rate in a giant and high mass star than in a low mass star.
A star 10 x the mass of siun can live upto 20 million years whereas low mass start has greater lifespan than the present age of the universe.
If you need to learn more about star energy click here:
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There Are Actually 5 So I Will Give You All.... Size Of Atom, Nuclear Charge, Screening Effect (Also Known As Sheilding Effect), Penetration Effect And Electronic Configuration
I believe it is the word is equilibrium because your body must kick on other systems if one is falling behind. Ex. You are cold so you shiver to keep warm.
Complete Question
The complete question is shown on the first uploaded image
Answer:
The magnitude is 
Explanation:
From the question we are told that
The distance between the spiders is 
The charge on the
is 
The charge on
is 
Given that the charge are arranged in an equilateral triangle, it implies that the angle at each vertices of the triangle is 60°
Generally the magnitude of net force on
is mathematically represented as

So

Here k is the columns constant with value 
So

=> 
From the diagram we see that 
So


Now from the diagram the ls [tex]270^o[\tex] counterclockwise from x-axis