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coldgirl [10]
3 years ago
8

A coin completes 18 spins in 12 seconds. The centripetal acceleration of the edge of the coin is 2.2 m/s2. The radius of the coi

n is m.
Physics
2 answers:
kompoz [17]3 years ago
4 0

Answer: 0.025 m or 2.5m

Explanation:

The number of spins given in 12 seconds = 18

So the number of spins in 1 second will be

= 18 / 12 = 1.5rps

The above result is the frequency because it is the number of spins in one second

Let f be frequency

f = 1.5 rps

Using centripetal acceleration given

Ca = 2.2 m/s^2

m is the radius of the given coin

Using the formula

Centripetal acceleration, = m x w^2

Knowing that w = 2πf

2.2 = m x ( 2 x 3.14 x 1.5) ^2

2.2 = m x 88.7364

m = 0.025 m

stellarik [79]3 years ago
3 0

Answer:

2.5 cm

Explanation:

Number of spins in 12 seconds = 18

Number of spins in 1 second = 18 / 12 = 1.5

Number of spins in one second is called frequency.

f = 1.5 rps

ac = 2.2 m/s^2

Let r be the radius of coin

Centripetal acceleration, ac = r x w^2

2.2 = r x ( 2 x 3.14 x 1.5) ^2

2.2 = r x 88.7364

r = 0.025 m = 2.5 cm

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A ball moving through the air.

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The ball has momentum which is a form of kinetic energy.

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A 26 foot ladder is lowered down a vertical wall at a rate of 3 feet per minute. The base of the ladder is sliding away from the
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Answer:

(i) 7.2 feet per minute.

(ii) No, the rate would be different.

(iii) The rate would be always positive.

(iv) the resultant change would be constant.

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Explanation:

Let the length of ladder is l, x be the height of the top of the ladder from the ground and y be the length of the bottom of the ladder from the wall,

By making the diagram of this situation,

Applying Pythagoras theorem,

l^2 = x^2 + y^2-----(1)

Differentiating with respect to t ( time ),

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\implies 2y\frac{dy}{dt} = -2x\frac{dx}{dt}

\implies \frac{dy}{dt}=-\frac{x}{y}\frac{dx}{dt}

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y = 10, \frac{dx}{dt}= -3\text{ feet per min}

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(i) From equation (1),

26^2 = x^2 + 10^2

676=x^2 + 100

576 = x^2

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From equation (X),

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(ii) From equation (X),

\frac{dy}{dt}\propto x

Thus, for different value of x the value of \frac{dy}{dt} would be different.

(iii) Since, distance = Positive number,

So, the value of y will always a positive number.

Thus, from equation (X),

The rate would always be a positive.

(iv) The length of the ladder is constant, so, the resultant change would be constant.

i.e. x = increases ⇒ y = decreases

y = decreases ⇒ y = increases

(v) if ladder hit the ground x = 0,

So, from equation (X),

\frac{dy}{dt}=0\text{ feet per min}

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