3 years ago

Help me plsssss I need. The question is confusing and so sorry if it blurry

Physics

1 answer:

Savatey [412]3 years ago

3 0

Answer:

400Pa

Explanation:

The question asks for you to substitiute in known values into the formula to solve for pressure which is calculated through force/area

in this instance

force=300N

area=0.75m^2

substitute in the values and solve for pressure

300/0.75=pressure

pressure=400Pa (the si unit for pressure is Pa or pascal)

You might be interested in

One indication that a planet may exist near a distant star is that ...

Bingel [31]

Shadows blocking part of the light from the star.

A quick warning though this only works on planets either close to the star or planets that are very large.

Also to ensure that the shadows are planets the shadows have to move or orbit around the star. IE The shadow moves

4 0

3 years ago

Determine the apple's kinetic energy, KE, the gravitational potential energy of the system, gravity, and the total mechanical en

guajiro [1.7K]

Answer:

7.45

Explanation:

At 3.0 m PE = m*g*3.0, KE = m*g*(4.0 - 3.0)

At 2.0 m PE = m*g*2.0, KE = m*g*(4.0 - 2.0)

At 3.0 m PE = m*g*1.0, KE = m*g*(4.0 - 1.0)

At 0 m PE = 0, KE = m*g*h = total energy = 7.45 J

6 0

3 years ago

A timeline is necessary a. For every goal c. For every life goal b. For every academic goal d. For every high school goal please

kiruha [24]

I’d say for every life goal

5 0

3 years ago

Read 2 more answers

A Ping-Pong ball has a mass of 2.3 g and a terminal speed of 9.1 m/s. The drag force is of the form bv2 What is the value of b?

meriva

At terminal velocity, drag force becomes equal to weight. Therefore:
weight = bv²
0.0023 x 9.81 = b x 9.1²
b = 2.72 x 10⁻⁴

7 0

3 years ago

Read 2 more answers

A student used a tuning fork of frequency 320 Hz and observed that the speed of sound was 339 m/s. Calculate the wavelength of t

Helen [10]

To solve this problem it is necessary to apply the concepts related to wavelength as a function of speed and frequency. In mathematical terms it can be expressed as

$\lambda = \frac{v}{f}$

Where,

v = Velocity

f = Frequency

According to our values the frequency (f) is 320Hz and the speed (v) is 339m / s.

Replacing in the given equation we have to,

$\lambda = \frac{v}{f}\\\lambda = \frac{339}{320}\\\lambda = 1.059m\approx 1.06m$

Therefore the wavelength of this sound wave is 1.06m

5 0

3 years ago