For question 1:
Part i)
2.6 x 2.6 = 6.76 cm squared
No unit conversions needed
Part ii)
1.2 dm = 1.2 / 1000000 = 0.0000012 cm
0.0000012 x 0.0000012 = 0.00000000000144 cm squared
Question 2:
16.5dm = 16.5/ 1000 = 0.0165 m
0.0165 x 0.0165 = 0.00027225 m squared
I hope this has helped
Answer:
13/6
Step-by-step explanation:
1 Simplify \sqrt{8}
8
to 2\sqrt{2}2
2
.
\frac{2}{6\times 2\sqrt{2}}\sqrt{2}-(-\frac{18}{\sqrt{81}})
6×2
2
2
2
−(−
81
18
)
2 Simplify 6\times 2\sqrt{2}6×2
2
to 12\sqrt{2}12
2
.
\frac{2}{12\sqrt{2}}\sqrt{2}-(-\frac{18}{\sqrt{81}})
12
2
2
2
−(−
81
18
)
3 Since 9\times 9=819×9=81, the square root of 8181 is 99.
\frac{2}{12\sqrt{2}}\sqrt{2}-(-\frac{18}{9})
12
2
2
2
−(−
9
18
)
4 Simplify \frac{18}{9}
9
18
to 22.
\frac{2}{12\sqrt{2}}\sqrt{2}-(-2)
12
2
2
2
−(−2)
5 Rationalize the denominator: \frac{2}{12\sqrt{2}} \cdot \frac{\sqrt{2}}{\sqrt{2}}=\frac{2\sqrt{2}}{12\times 2}
12
2
2
⋅
2
2
=
12×2
2
2
.
\frac{2\sqrt{2}}{12\times 2}\sqrt{2}-(-2)
12×2
2
2
2
−(−2)
6 Simplify 12\times 212×2 to 2424.
\frac{2\sqrt{2}}{24}\sqrt{2}-(-2)
24
2
2
2
−(−2)
7 Simplify \frac{2\sqrt{2}}{24}
24
2
2
to \frac{\sqrt{2}}{12}
12
2
.
\frac{\sqrt{2}}{12}\sqrt{2}-(-2)
12
2
2
−(−2)
8 Use this rule: \frac{a}{b} \times c=\frac{ac}{b}
b
a
×c=
b
ac
.
\frac{\sqrt{2}\sqrt{2}}{12}-(-2)
12
2
2
−(−2)
9 Simplify \sqrt{2}\sqrt{2}
2
2
to \sqrt{4}
4
.
\frac{\sqrt{4}}{12}-(-2)
12
4
−(−2)
10 Since 2\times 2=42×2=4, the square root of 44 is 22.
\frac{2}{12}-(-2)
12
2
−(−2)
11 Simplify \frac{2}{12}
12
2
to \frac{1}{6}
6
1
.
\frac{1}{6}-(-2)
6
1
−(−2)
12 Remove parentheses.
\frac{1}{6}+2
6
1
+2
13 Simplify.
\frac{13}{6}
6
13
Done
Answer: x= -12
Step-by-step explanation:
These are corresponding angles which means they are the same. X+62= 50. Subtract 62 from both sides. X= -12
H = 60 + 8x
h = Tree's height in inches
x = years of growth
Answer:
4
Step-by-step explanation:
Given that three pairs of gloves- a red pair, a blue pair, and a green pair-are in a drawer. The gloves are removed at random without returning any to the drawer.
We have to find the minimum number that must be removed in order to guarantee having a matched pair of gloves
No of different colours = 3 (red, blue, green)
Hence no of gloves that must be removed = 3+1
If 4 gloves are removed, only 3 can be of different colours 1 will have same colour as any one of the three.
So a pair of same colour would be obtained
Answer is 4
