Find the length of a side of a square with an area of 169 in^2.
Answer:
D. 13 in
Step-by-step explanation:
A square has sides of equal length.
A = L^2 where: A = area and L = side
L^2 = 169
L=√169
L=13 in^2.
First, we have
s1/r1 = s2/r2
The question also states the fact that
s/2πr = θ/360°
Rearranging the second equation, we have
s/r = 2πθ/360°
Then we substitute it to the first equation
s1/r1 = 2πθ1/360°
s2/r2 = 2πθ2/360°
which is now
2πθ1/360° = 2πθ2/360°
By equating both sides, 2π and 360° will be cancelled, therefore leaving
θ1 = θ2
Answer:
Step-by-step explanation:
if (h,k) is the center and r be radius of circle.
Then eq. of circle is (x-h)^2+(y-k)^2=r^2
reqd. eq. of circle is (x+4)²+(y+5)²=(√6)²
or (x+4)²+(y+5)²=6
Answer:
First lets find the solutions to each inequality.
-2x
10 and -2x>10 (divide both sides by -2 to solve)
x
-5 and x<-5
x
-5 tell us that x could be -5 or less.
x<-5 tells us that x could be -6 or less.
The first one is less than or equal to which tells you that there is a possibility that the number is shows is could be an answer
Hope this helps ;)
Answer:
Step-by-step explanation:
First, you should put the axis of symetry as 5, -7 because f(x)= (x-h)^2+k and h is 5 and k is -7. the axis of symetry is x=5 because that is the "folding point" of the graph. Next, you would have to plug In 4 and 6 as your helping points to tell you where the other points of the function are going to be.
Plug 4 in and you get -6. plug 6 in and you get -6. plot the points (4, -6) and (6,-6).
Hope this helps!
:)