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stira [4]
3 years ago
9

The air strips at high altitude airports are longer than those at sea level. What would be the reason for this? Explain using sc

ientific language.
Physics
1 answer:
Eddi Din [679]3 years ago
6 0

Answer:

The lower air density at high altitudes means that a faster air speed is need for a given amount of lift. In order to get the higher air speed, an airplane must accelerate for a longer amount of time, and thus a longer runway is required.

Explanation:

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The largest building in the world by volume is the boeing 747 plant in Everett, Washington. It measures approximately 632 m long
Schach [20]

Explanation:

Given that,

The dimensions of the largest building in the world is 632 m long, 710 yards wide, and 112 ft high. It basically forms a cuboid. The volume of a cuboidal shape is given by :

Since,

1 meter = 3.28084 feet

632 m = 2073.49 feet

1 yard= 3 feet

710 yards = 2130 feet

V = lbh

V=2073.49 \ ft\times 2130\ ft\times 112\ ft

V=494651774.4\ ft^3

V=4.94\times 10^8\ ft^3

Also,

V=(4.94\times 10^8\ ft^3)(\dfrac{1\ m}{3.281})^3

V=1.39\times 10^7\ m^3

Hence, this is the required solution.

3 0
4 years ago
The forces acting on a sailboat are 390n north and 180n east. if the boat (including crew) has a mass of 270 kg, what are the ma
patriot [66]
F=ma so a=F/m

ax=180/270=0.67m/s^2
ay=390/270=1.44m/s^2

Magnitude = sqrt((0.67^2)+(1.44^2))=1.59m/s^2

Direction- Tan(x)=0.67/1.44=0.47 Tan^-1(x)=25 degrees
4 0
3 years ago
Read 2 more answers
Which part of the electromagnetic spectrum has a lower frequency than visible light?
Mademuasel [1]

The Correct Answer is <u>D.Infrared/</u> <em>INFARED has a lower frequency than visible light/</em>

6 0
3 years ago
Read 2 more answers
Se pune<br>Numerical problems<br>Convert 100ºC to Kelvin scale​
IgorC [24]

Answer:

373 K

Explanation:

To convert from °C to kelvin, you add the value to 273

Therefore,

100°C = (100+273)K

= 373K

5 0
4 years ago
Sam, whose mass is 75 kg, straps on his skis and starts down a 50-m-high, 20 frictionless slope. A strong headwind exerts a hori
LenaWriter [7]

Answer:

Explanation:

Sam mass=75kg

Height is 50m

20° frictionless slope

Horizontal force on Sam is 200N

According to the work energy theorem, the net work done on Sam will be equal to his change in kinetic energy.

Therefore

Wg - Ww =∆K.E

Note initial the body was at rest at top of the slope.

Then, ∆K.E is K.E(final) - K.E(initial)

K.E Is given as ½mv²

Since initial velocity is zero then, K.E(initial ) is zero

Therefore, ∆K.E=½mVf²

Wg is work done by gravity and it is given by using P.E formulas

Wg=mgh

Wg=75×9.8×50

Wg=36750J

Ww is work done by wind and it's is given by using formulae for work

Work=force × distance

Ww=horizontal force × horizontal distance

Using Trig.

TanX=opposite/adjacent

Tan20=h/x

x=h/tan20

x=50/tan20

x=137.37m

Then,

Ww=F×x

Ww=200×137.37

We=27474J

Now applying the formula

Wg - Ww =∆K.E

36750 - 27474 =½×75×Vf²

9276=37.5Vf²

Vf²=9275/37.5

Vf²= 247.36

Vf=√247.36

Vf=15.73m/s

3 0
4 years ago
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