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mariarad [96]
4 years ago
14

How many 5 digit codes are possible if the first digit cannot be 0 or 1 and digits can be repeated?

Mathematics
1 answer:
lisov135 [29]4 years ago
5 0

Answer:

80000

Step-by-step explanation:

The first digit is the only one with any constraints: it cannot be 1 or 0. This leaves us with 8 options (2, 3, 4, 5, 6, 7, 8, 9).

The other four digits have no such conditions, so we have 10 choices for each of them (0-9, inclusive).

So!

8 * 10 * 10 * 10 * 10 = 80000 :))

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