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2 years ago

Answer and show proof for brainliest

Mathematics

2 answers:

Yanka [14]2 years ago

8 0

1. add all value together: 24+31+12+38+12+15= 132

2. divide answer by amount of numbers added together: 132/6=22

3. Answer: the mean is 22

kodGreya [7K]2 years ago

3 0

Answer:

Step-by-step explanation:

Add each number given = 132

132 / 6 (amount of given numbers)

=12

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In a set of real numbers, the first number less then -3 is -4<br> true <br> or<br> false

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true

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The function f(x) is given by the set of orderd pairs.

Alecsey [184]

Answer:

F(-6)=10

Step-by-step explanation:

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The last choice is the correct option

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2 years ago

Find the area of a triangle whose sides are 5 m, 6 m and 9m,( use root 2 =-1.41 m)

dlinn [17]

The area of the triangle is 14.1 square meters

<h3>How to determine the triangle area?</h3>

The side lengths are given as:

5m, 6m and 9m

Calculate the semi-perimeter (s) using

s = (5 + 6 + 9)/2

Evaluate

s = 10

The area is then calculated as:

$Area = \sqrt{s(s -a)(s-b)(s-c)$

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Area = 14.1

Hence, the area of the triangle is 14.1 square meters

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2 years ago

Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions th

trasher [3.6K]

Answer:

(a) 100 fishes

(b) t = 10: 483 fishes

t = 20: 999 fishes

t = 30: 1168 fishes

(c)

$P(\infty) = 1200$

Step-by-step explanation:

Given

$P(t) =\frac{d}{1+ke^-{ct}}$

$d = 1200\\k = 11\\c=0.2$

Solving (a): Fishes at t = 0

This gives:

$P(0) =\frac{1200}{1+11*e^-{0.2*0}}$

$P(0) =\frac{1200}{1+11*e^-{0}}$

$P(0) =\frac{1200}{1+11*1}$

$P(0) =\frac{1200}{1+11}$

$P(0) =\frac{1200}{12}$

$P(0) = 100$

Solving (a): Fishes at t = 10, 20, 30

$t = 10$

$P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483$

$t = 20$

$P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999$

$t = 30$

$P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168$

Solving (c): $\lim_{t \to \infty} P(t)$

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of $e^{-ct}$ decreases

This implies that:

${t \to \infty} = {e^{-ct} \to 0}$

So:

The value of P(t) for large values is:

$P(\infty) = \frac{1200}{1 + 11 * 0}$

$P(\infty) = \frac{1200}{1 + 0}$

$P(\infty) = \frac{1200}{1}$

$P(\infty) = 1200$

5 0

2 years ago