(a) The "average value" of a function over an interval [a,b] is defined to be
(1/(b-a)) times the integral of f from the limits x= a to x = b.
Now S = 200(5 - 9/(2+t))
The average value of S during the first year (from t = 0 months to t = 12 months) is then:
(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12
or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12
This equals 200/12 * (5t -9ln(2+t))
Evaluating this with the limits t= 0 to t = 12 gives:
708.113 units., which is the average value of S(t) during the first year.
(b). We need to find S'(t), and then equate this with the average value.
Now S'(t) = 1800/(t+2)^2
So you're left with solving 1800/(t+2)^2 = 708.113
<span>I'll leave that to you</span>
<span>A Zoo has two male lions. one sixth of the Lions are male lions. how many lions are there at the zoo?There are 12 lions.</span>
Answer:
41.79%
Step-by-step explanation:
To be on the swim team, we look at the right most (total) number int he table of "on the swim team" row. That is 28.
The grand total is the bottom-rightmost. That is 67.
Hence, probability of being on swim team is 28/67 = 41.79%
Answer
a
Step-by-step explanation:
because submarine b has a bigger negative number so its more further down