Answer:
See explanation
Step-by-step explanation:
1 step:
n=1, then

So, for j=1 this statement is true
2 step:
Assume that for n=k the following statement is true

3 step:
Check for n=k+1 whether the statement

is true.
Start with the left side:

According to the 2nd step,

Substitute it into the 

So, you have proved the initial statement
Answer:
0.75
Step-by-step explanation:
there is 1000 grams in 1 kilogram so I divided 750 by 1000 to get 0.75.
Answer:
1.) step No.3 x(2x-5) - (2x-5)
2.) 16 +28i-28i - 49i²
but we know i² = -1
the expression becomes
16 + 49
= 66
Answer:
Step 1: 3*4=12
Step 2: 12+3=15
Step 3: 15-10=5
Step-by-step explanation:
Answer:
43.20 for the total cost of the item