Answer:
The proof is explained step-wise below :
Step-by-step explanation :
For better understanding of the solution see the attached figure :
Given : ABCD is a Parallelogram ⇒ AB ║ DC and AD ║ BC
Now, F lies on the extension of DC. So, AB ║ DF
To Prove : ΔABE is similar to ΔFCE
Proof :
Now, in ΔABE and ΔFCE
∠ABE = ∠FCE ( alternate angles are equal )
∠AEB = ∠FEC ( Vertically opposite angles )
So, by using AA postulate of similarity of triangles
ΔABE is similar to ΔFCE
Hence Proved.
Given:
There are given that the parent functions as a cosine function:
Where,
The amplitude of the function is 9.
The vertical shift is 11 units down.
Explanation:
To find the cosine function, we need to see the standard form of the cosine function:
Where,
a is the amplitude of the function,
Now,
According to the question:
The amplitude of the function is 9, which means:
The vertical shift is 11 units down, which means:
For period:
Final answer:
Hence, the cosine function is shown below;
Answer:
B. Square
Step-by-step explanation:
When in doubt, it can help to plot the points on a graph.
__
By looking at the coordinate values, you see that the first two points have the same y-coordinate (0) and the other two points have the same y-coordinate (-4). These points are on horizontal lines that are 4 units apart.
Looking at the x-coordinates, you see that one pair of points has x-coordinates 4, and the other pair has x-coordinates 8. That is, these pairs of points are on vertical lines that are 4 units apart.
Vertical and horizontal lines are at right angles to each other. That means the figure must be a rectangle or square. The lengths of the sides are all 4 units, so the figure is a square.
