What is the area of the triangle below

Mathematics

2 answers:

jonny [76]3 years ago

8 0

Answer:

Option D is correct.

65 square units

Step-by-step explanation:

Area of right triangle(A) is given by:

$A = \frac{1}{2} \cdot b \cdot h$ ......[1]

where,

b is the base of the triangle

h is the height of the triangle.

As per the statement:

In the given right angle triangle:

Base(b) = 13 units

Height(h) = 10 units

Substitute in [1] we have;

$A = \frac{1}{2} \cdot 13 \cdot 10 = 13 \cdot 5 = 65$ square units

Therefore, the area of triangle is, 65 square units

Zinaida [17]3 years ago

7 0

Ok so you take 13 and multiply it by 10 then divide that product by 2.(13x10)/2= 65 (D.)

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myrzilka [38]

Answer:

$x_1=\frac{1+\sqrt{61}}{6}\approx1.47,x_2=\frac{1-\sqrt{61}}{6}\approx-1.14$

Step-by-step explanation:

To solve a non-factorable quadratic equation in the form of $ax^2+bx+c=0$ , you need to use the quadratic formula where $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ :

$3x^2+x-5=0$

$x=\frac{-1\pm\sqrt{1^2-4(3)(-5)}}{2(3)}$

$x=\frac{-1\pm\sqrt{1+60}}{6}$

$x=\frac{-1\pm\sqrt{61}}{6}$

Because of the $\pm$ sign, quadratic equations always have two solutions, whether both are real, only one is real, or both are complex (in the form of $a+bi$ where $a$ is the real part and $b$ is the imaginary part where $i=\sqrt{-1}$ ). In this case, because the discriminant is positive (defined as $b^2-4ac$ ), then there are 2 real solutions.