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frosja888 [35]
3 years ago
8

g A 45.0 - kg girl is standing on a 150. - kg plank. The plank, originally at rest, is free to slide on a frozen lake, which is

a flat, frictionless surface. The girl begins to walk along the plank at a constant velocity of 1.50 m/s to the right relative to the plank. (a) What is her velocity relative to the surface of the ice
Physics
2 answers:
vampirchik [111]3 years ago
5 0

Answer:

her velocity relative to the surface of the ice is 1.154 m/s

The positive velocity indicates that her velocity relative to the surface of the ice is in the same direction with her velocity relative to plank.

Explanation:

Given;

mass of the girl, M_G = 45.0 - kg

mass of the plank, M_P = 150 kg

velocity of the girl relative to the plank, V_G_P = 1.5 m/s

Velocity of the plank relative to the ice, V_P_I = ?

Velocity of the girl relative to the ice, V_G_I = ?

Thus, velocity of the girl relative to the ice can be calculated as;

V_G_I = V_G_P  + V_P_I

V_G_I = 1.5 + V_P_I -----------equation (i)

From the principle of conservation of energy;

M_GV_{GI} +M_PV_{PI} = 0

45V_G_I + 150 V_P_I = 0

3V_G_I +  10V_P_I = 0 ------------equation (ii)

From equation (i);  V_P_I = V_G_I - 1.5

Substitute in  V_P_I in equation (ii)

3V_G_I +  10( V_G_I - 1.5) = 0

3V_G_I + 10V_G_I -15 = 0

13V_G_I = 15

V_G_I = 15/13

V_G_I = 1.154 m/s

The positive velocity indicates that her velocity relative to the surface of the ice is in the same direction with her velocity relative to plank.

oksian1 [2.3K]3 years ago
4 0

Answer:

velocity of girl with respect  to surface of ice 1.154 m/s

Explanation:

Plank Mass , M = 150 kg

Girl Mass , m = 45 kg

velocity of the girl with resect to plank, v1 = 1.50 m/s

velocity of the plank + girl = v2

from the conservation of momentum

Momentum (plank+girl) = - momentum of the girl

(M+m)v2 = -mv1

v2 = -(45 kg)/(195 kg) * 1.50

v2 = -0.346 m/s

velocity of girl with respect  to surface of ice =

  v1+v2 = 1.50 + (-0.346) = 1.154 m/s

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