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3 years ago

In the chemical equation above, the small number after the O in 1202 represent —

Physics

1 answer:

Murrr4er [49]3 years ago

7 0

Answer:

G.) The number atoms of that element in the molecule

Explanation:

F is incorrect because the coefficient represents the amount of one type of molecule, not the subscript

G is correct because subscripts represent how many atoms of that element are present in that single molecule

H is incorrect because energy is not represented in this simple type of equation

J is incorrect because it doesn't even make sense

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A11) A solenoid of length 18 cm consists of closely spaced coils of wire wrapped tightly around a wooden core. The magnetic fiel

vitfil [10]

Answer:

Explanation:

From a Solenoid we know that a magnetic fiel is always inversely proportional to lenght L or BL = constant

$B= frac{\mu_0}{2R}$

As I is constant

$\frac{B2}{B1} = \frac{R1}{R2}$

$B2 = 2mT*\frac{18}{21}$

$B2 = 1.714mT$

7 0

3 years ago

Question 29 of 43

liraira [26]

I agree with the first responses

3 0

3 years ago

An object is traveling with a constant velocity of 5 m/s. How far will it have gone after 7 s?

kozerog [31]

<h3>Answer:</h3>

35 meters

<h3>Explanation:</h3>

<u>Data given;</u>

Velocity of an object = 5 m/s
Time taken = 7 s

We are required to calculate how far the object traveled.

We need to know that;

Velocity = Displacement ÷ time

Therefore;

Displacement = Velocity × time

= 5 m/s × 7 s

= 35 m

Therefore; the object traveled 35 meters

6 0

3 years ago

You are given a sample of metal and asked to determine its specific heat. You weight the sample and find that its weight is 28.4

lidiya [134]

Answer:

The samples specific heat is 14.8 J/kg.K

Explanation:

Given that,

Weight = 28.4 N

Suppose, heat energy $E=1.25\times10^{4}\ J$

Temperature = 18°C

We need to calculate the samples specific heat

Using formula of specific heat

$Q=mc\Delta T$

$c=\dfrac{Q}{m\Delta T}$

Where, m = mass

c = specific heat

$\Delta T$ = temperature

Q = heat

Put the value into the formula

$c=\dfrac{1.25\times10^{4}}{\dfrac{28.4}{9.8}\times(18+273)}$

$c=14.8\ J/kg. K$

Hence, The samples specific heat is 14.8 J/kg.K

8 0

3 years ago

How long does it take a microwave of power 0.2kW to sue 10000 J of energy

olasank [31]

Answer:

50s .

Explanation:

$\frak{\pink{Given}}\begin{cases}\textsf{ The power of microvave is 0.2kW .}\\\textsf{ Amount of energy is 10000 J .}\end{cases}$

Here the power of the microwave is 0.2kW . And as we know that ,

Rate of doing work is called power .

So from the definition , we have ;

$\sf\longrightarrow Power =\dfrac{Work}{time}$

Here the work done is equal to the energy consumed by the microwave i.e. 10000 J .So we can write it as ,

$\sf\longrightarrow Power =\dfrac{Energy}{time}$

$\sf\longrightarrow 0.2kW = \dfrac{10^4 J }{t} \\$

$\sf\longrightarrow 0.2 * 1000 W = \dfrac{10^4 J }{t}$

Cross multiply ,

$\sf\longrightarrow t = \dfrac{ 10^4 }{ 0.2 * 10^3}s=\dfrac{10^4}{2*10^2} s$

Simplify ,

$\sf\longrightarrow \boxed{\bf t = 50s}$

<h3>Hence the time taken is 50s .</h3>

5 0

2 years ago