A car starts at rest and accelerates at a rate of 4 m/s^2. How far does the car travel in 5
1 answer:
Answer:
C. 50m
Explanation:
Given parameters:
Initial velocity = 0m/s
Acceleration = 4m/s²
Time of travel = 5s
Unknown:
distance covered = ?
Solution:
To solve this problem, we use the expression below;
S = ut + at²
S is the distance
u is the initial speed
t is the time
a is the acceleration
S = (0x 5) + x 4 x 5² = 50m
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Answer:
6.96 s
Explanation:
<u>Given:</u>
- u = initial speed of the automobile = 0 m/s
- a = constant acceleration of the automobile =
- v = constant speed of the truck = 8.7 m/s
<u>Assume:</u>
- t = time instant at which the automobile overtakes the truck.
At the moment the automobile and the truck both meat each other the distance travel by both vehicles must be the same.
Since t = 0 s is the initial condition. So, they both meet again at t = 6.96 s such that the automobile overtakes the truck.
Answer:
a. Final velocity, V = 2.179 m/s.
b. Final velocity, V = 7.071 m/s.
Explanation:
<u>Given the following data;</u>
Acceleration = 0.500m/s²
a. To find the velocity of the boat after it has traveled 4.75 m
Since it started from rest, initial velocity is equal to 0m/s.
Now, we would use the third equation of motion to find the final velocity.
Where;
- V represents the final velocity measured in meter per seconds.
- U represents the initial velocity measured in meter per seconds.
- a represents acceleration measured in meters per seconds square.
- S represents the displacement measured in meters.
Substituting into the equation, we have;
Taking the square root, we have;
<em>Final velocity, V = 2.179 m/s.</em>
b. To find the velocity if the boat has traveled 50 m.
Taking the square root, we have;
<em>Final velocity, V = 7.071 m/s.</em>