A car starts at rest and accelerates at a rate of 4 m/s^2. How far does the car travel in 5
1 answer:
Answer:
C. 50m
Explanation:
Given parameters:
Initial velocity = 0m/s
Acceleration = 4m/s²
Time of travel = 5s
Unknown:
distance covered = ?
Solution:
To solve this problem, we use the expression below;
S = ut + at²
S is the distance
u is the initial speed
t is the time
a is the acceleration
S = (0x 5) + x 4 x 5² = 50m
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Explanation:
It is given that,
Speed, v₁ = 7.7 m/s
We need to find the velocity after it has risen 1 meter above the lowest point. Let it is given by v₂. Using the conservation of energy as :
So, the velocity after it has risen 1 meter above the lowest point is 6.26 m/s. Hence, this is the required solution.