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ladessa [460]
4 years ago
13

A remote control car is traveling at a velocity of 0.50 m/s when it hits a wall and comes to a stop in 0.050 seconds. What is th

e acceleration of the car?
Physics
1 answer:
OlgaM077 [116]4 years ago
7 0

Answer:0.50m/s divide by 0.050sec = 10m/s

Explanation: dividing the meter per second [m/s] by the second [s

You might be interested in
The friction force that acts on objects that are at rest is___________
weeeeeb [17]

Answer:

static friction

Explanation:

static friction is the friction force that acts on objects at rest

7 0
3 years ago
Paco was driving his scooter west with an initial velocity of 4 m/s. He accelerates at 0.5 m/s2 for 30 seconds.
KonstantinChe [14]

Answer:

V = 19m/s

Explanation:

Given the following data;

Initial velocity, U = 4m/s

Acceleration, a = 0.5m/s²

Time, t = 30 seconds

To find the final velocity, we would use the first equation of motion;

V = U + at

Where;

V is the final velocity.

U is the initial velocity.

a is the acceleration.

t is the time measured in seconds.

V = 4 + 0.5*30

V = 4 + 15

V = 19m/s

Therefore, his final velocity is 19 meters per seconds.

6 0
3 years ago
Read 2 more answers
UWU plz help 50 points!!
OleMash [197]

Answer:

i think its 20m for b

Explanation:

7 0
3 years ago
In Ancient Greece, athletes competing in the long jump used handheld weights called halteres to lengthen their jumps. You are a
katovenus [111]

The halter add the distance to the jump in meters is 0.55 m.

<h3>What is projectile?</h3>

When an object is thrown at an angle from the horizontal direction, the object is said to be in projectile motion. The object which follows the projectile motion is called the projectile.

The magnitude of velocity u =10.3 m/s, angle of jumping θ = 22.8 degrees.

Components of velocity in x and y direction are

Vx = 10.3 cos 22.8 = 9.5 m/s

Vy = 10.3 sin 22.8 = 4 m/s

Maximum Range of athlete achieved using halter is given by

R = u²sin2θ /g

where, u = initial velocity, θ is the angle of projection and g is the gravitational acceleration.

Substituting the values, we get

R = (10.3)² sin(2 x 22.8 °) / 2 x 9.81

R = 7.75m

At the peak of jump you throw two 5.5 kg masses horizontally behind you such that their velocity is zero in the ground's reference frame.

The momentum is conserved in this situation,

(M+2m)Vxo =MVx'

Vx' = (M+2m)/M x Vxo'

Change in x component of velocity ΔVx = Vx' -Vxo

Vxo = 2m/M x Vx

Vxo = 2 x 5.5 /78 x 9.5

Vxo = 1.34 s

Maximum height gained when final velocity is zero

Vy = 0 = Vyo -gt

time t = Vyo/g = 4/9.8 = 0.41s'

Increase in range by using of halters is

ΔR = ΔVx' x t

ΔR = 1.34 x 0.41

ΔR =0.55m

Thus, the halter add the distance to the jump in meters is 0.55 m.

Learn more about projectile.

brainly.com/question/11422992

#SPJ1

3 0
2 years ago
At which position is the northern hemisphere experiencing winter?
Leto [7]

The answer would be point A.

Hope this helped you.

6 0
4 years ago
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