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Alenkasestr [34]
3 years ago
8

a sporting goods store sells 2 fishing rods and 4 fishing reels for $184. Later they sell 6 fishing reels and 3 fishing rods for

$489. Find the price of each item.
Mathematics
2 answers:
sertanlavr [38]3 years ago
7 0

Answer:

Step-by-step explanation:

Let the fishing rod be x

Let the fishing reel be y

2x+4y=183..(1)

3x+6y=489...(2)

Multiply (1) by 3

6x+12y=549...(3)

Multiply (2) by 2

6x+12y=978...(4)

Klio2033 [76]3 years ago
5 0

Answer:

fishing rod = $78, fishing reel=$7

Step-by-step explanation:

A fishing rod: x

A fishing reel: y

2x+4y=184

6x+3y=489

Simplify.

x+2y=92

2x+y=163

Add the equations.

3x+3y=255

Multiply by 2/3.

2x+2y=170

subtract.

x=78

y=7

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Nd the 52nd term and the term named in the problem <br>40, 140, 240, 340, ...<br>Find a 32​
Galina-37 [17]

Answer:

5140 and 3140

Step-by-step explanation:

Note there is a common difference d between consecutive terms in the sequence, that is

d = 140 - 40 = 240 - 140 = 340 - 240 = 100

This indicates the sequence is arithmetic with n th term

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 40 and d = 100, thus

a_{52} = 40 + (51 × 100) = 40 + 5100 = 5140

a_{32} = 40 + (31 × 100) = 40 + 3100 = 3140

5 0
3 years ago
Find the inverse of ????−7 −2
Masja [62]

Answer:

A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}

Step-by-step explanation:

A=\begin{bmatrix}-7 & -2\\ 4 & 1\end{bmatrix}

det\ A=-7\times 1-(-2)\times 4\\\Rightarrow det\ A=1

A^{-1}=\frac{1}{det\ A}\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A^{-1}=\frac{1}{1}\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}

\therefore A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}

A.A^{-1}=\begin{bmatrix}-7 & -2\\ 4 & 1\end{bmatrix}\times \begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A.A^{-1}=\begin{pmatrix}\left(-7\right)\cdot \:1+\left(-2\right)\left(-4\right)&\left(-7\right)\cdot \:2+\left(-2\right)\left(-7\right)\\ 4\cdot \:1+1\cdot \left(-4\right)&4\cdot \:2+1\cdot \left(-7\right)\end{pmatrix}\\\Rightarrow A.A^{-1}=\begin{pmatrix}1&0\\ 0&1\end{pmatrix}

Hence, confirmed

6 0
4 years ago
Joe owns a stock which has probability .5 of going up. This morning, he bought a ticket in a lottery game which gives him a prob
Anit [1.1K]

Answer:

The probability that Joe's stock will go up and he will win in the lottery  is 0.00005.

Step-by-step explanation:

Let the events be denoted as:

<em>X</em> = the stock goes up

<em>Y</em> = Joe wins the lottery

Given:

P (X) = 0.50

P (Y) = 0.0001

The events of the stock going up is not dependent on the the event of Joe winning the lottery.

So the events <em>X</em> and <em>Y</em> are independent of each other.

Independent events are those events that can occur together at the same time.

The joint probability of two independent events <em>A</em> and <em>B </em>is,

P(A\cap B)=P(A)\times P(B)

Compute the value of P (<em>X ∩ Y</em>) as follows:

P(X\cap Y)=P(X)\times P(Y)=0.50\times 0.0001=0.00005

Thus, the probability that Joe's stock will go up and he will win in the lottery  is 0.00005.

3 0
3 years ago
Read 2 more answers
I rlly need to know this asap
balu736 [363]
Box A has 12 balls and Box B has 8 balls.
OR
Box A has 60 balls and Box B has 40 balls.
OR
Box A has 48 balls and Box B has 32 balls.
7 0
3 years ago
In the figure below, F is between E and G, and G is between F and H. IF EH=9, FH = 7, and EG=6, find FG.
shutvik [7]

Answer:

EH = 9

FH = 7

EG = 6

EF = EH - FH

EF = 9 -7

EF = 2

FG = EG -EF

FG = 6 -2

FG = 4

Step-by-step explanation:

3 0
4 years ago
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