Answer:
3
Explanation:
according according to me option b is correct
Answer:
ΔSº= -41,2 J/molK
Explanation:
For a general equation aA +bB → cC + dD
ΔSº= c*SºC + d*SºD - a*SºA - b*SºB
ΔSº= SºAL2O3 + 2SºFe - SºFe2O3 - 2SºAl = (51 + 54.4 - 90 - 56.6)J/molK = -41,2 J/molK
Answer:
0.5 × 10²³ atoms of iodine
Explanation:
Given data:
Mass of calcium iodide = 12.75 g
Number of atoms of iodine = ?
Solution:
First of all we will calculate the number of moles of calcium iodide.
Number of moles = mass/ molar mass
Number of moles = 12.75 g/ 293.9 g/mol
Number of moles = 0.04 mol
In one mole of calcium iodide there are two moles of iodine.
Thus in 0.04 moles:
0.04 mol × 2 = 0.08 moles of iodine
Now we will use the Avogadro number:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
1 mole = 6.022 × 10²³ atoms
0.08 moles of iodine × 6.022 × 10²³ atoms / 1 mol
0.5 × 10²³ atoms of iodine.
Answer:
High heat and low pressure.