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o-na [289]
3 years ago
15

How many atoms of iodine are in 12.75g of CaI2

Chemistry
1 answer:
dexar [7]3 years ago
8 0

Answer:

0.5  × 10²³ atoms of iodine

Explanation:

Given data:

Mass of calcium iodide = 12.75 g

Number of atoms of iodine = ?

Solution:

First of all we will calculate the number of moles of calcium iodide.

Number of moles = mass/ molar mass

Number of moles = 12.75 g/ 293.9 g/mol

Number of moles = 0.04 mol

In one mole of calcium iodide there are two moles of iodine.

Thus in 0.04 moles:

0.04 mol × 2 = 0.08 moles of iodine

Now we will use the Avogadro number:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

0.08 moles of iodine × 6.022 × 10²³ atoms / 1 mol

0.5  × 10²³ atoms of iodine.

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water evaporates because when h2o (water) particles heat up, they gain energy causing them to start to vibrate. this moves the oarticles further and further away from eachother and making the substance less dense, and turning it into a gas. meaning it has evaporated

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What is the H+ in solution with pH of 10.9
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3 years ago
Once an enzymatic reaction is completed, the enzyme releases what?
sleet_krkn [62]

Answer:

Once an enzymatic reaction is completed, the enzyme releases substrates.

Explanation:

The enzyme will always return to its original state at the completion of the reaction. One of the important properties of enzymes is that they remain ultimately unchanged by the reactions they catalyze. After an enzyme is done catalyzing a reaction, it releases its products (substrates).

5 0
2 years ago
An ordered list of chemical substances is shown. Chemical Substances 1 CuO 2 O2 3 CO2 4 NO2 5 Fe 6 H2O Which substances in the l
a_sh-v [17]

Answer:

reactants: 2 O2

products: 3 CO2, 4 NO2, 6 H2O

Explanation:

In a combustion, a combustible material, which generally is composed of C, H, O, N, and S, is combusted, that is, react with oxygen after a spark was produced; obtaining fire, heat and subproducts, including ashes and gases.

Oxygen is always one of the reactants of a combustion.

If Nitrogen was present in the combustible, NO2 (or other nitrogen oxides) will be produced.

If Carbon was present in the combustible, CO2 will be produced (also CO can be produced).

If Hydrogen was present in the combustible, H2O will be produced.

7 0
3 years ago
A salt contains only barium and one of the halide ions. A 0.158 g sample of the salt was dissolved in water, and an excess of su
Delvig [45]

Answer:

BaBr2

Explanation:

Halide ions are the ions of the elements of group 17 (or 7A), which have 7 electrons in their valence shell, so they need to gain one electron to be stable. If we noted as X the halide, the ion must be X^{-}.

Barium is a metal of group 2 (or 2A) and has 2 electrons in its valence shell, so it must lose these 2 electrons to be stable, and it will form the anion Ba^{2+}. These elements will form an ionic bond, with formula BaX2.

Sulfuric acid has formula H2SO4, and the reaction is:

BaX2 + H2SO4 --> BaSO4 + 2HX

So, for the stoichiometry between BaX2 and BaSO4, and denoting by <em>y</em> the molar mass of the halide, and the molar mass of BaSO4 = 137.33 g of Ba + 32.06 g of S + 4x16 g of O = 233.39

1 mol of BaX2 ------------- 1 mol of BaSO4

(137.33 + 2y) g of BaX2 ------------ 233.39 g of BaSO4

0.158 g of BaX2 --------------------- 0.124 g of BaSO4

By a simple direct three rule:

0.124x(137.33 + 2y) = 0.158x233.39

17.02892 + 0.248y = 36.87562

0.248y = 19.8467

y = 19.8467/0.248

y = 80.03 g/mol

By consulting the periodic table, the halide element that has a molar mass close to 80.03 g/mol is Bromide (Br), which has molar mass 79.9 g/mol. So the salt has formula BaBr2.

8 0
3 years ago
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