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o-na [289]
4 years ago
15

How many atoms of iodine are in 12.75g of CaI2

Chemistry
1 answer:
dexar [7]4 years ago
8 0

Answer:

0.5  × 10²³ atoms of iodine

Explanation:

Given data:

Mass of calcium iodide = 12.75 g

Number of atoms of iodine = ?

Solution:

First of all we will calculate the number of moles of calcium iodide.

Number of moles = mass/ molar mass

Number of moles = 12.75 g/ 293.9 g/mol

Number of moles = 0.04 mol

In one mole of calcium iodide there are two moles of iodine.

Thus in 0.04 moles:

0.04 mol × 2 = 0.08 moles of iodine

Now we will use the Avogadro number:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

0.08 moles of iodine × 6.022 × 10²³ atoms / 1 mol

0.5  × 10²³ atoms of iodine.

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Pachacha [2.7K]

Answer:

bends and slides under one another

Explanation:

"Where two tectonic plates meet at a subduction zone, one bends and slides underneath the other, curving down into the mantle."

4 0
3 years ago
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ethanol has a density of 0.789 g/cm3, how many pounds of ethanol would be in a drum containing 7.0 gallons of ethanol
max2010maxim [7]

From the density of ethanol given, the number of pounds of ethanol in the drum will be 46.099 pounds.

<h3>How to calculate density</h3>

Density of ethanol = 0.789/cm³

1 gallon = 3785.4ml

Volume of ethanol = 7 gallons = 7 × 3785.4ml = 26497.8ml

Mass of ethanol = Volume × Density.

= 26497.8 × 0.789

= 20906.764g

Since 1g = 0.002205 pounds, the mass of ethanol will be:

= 20906.764 × 0.002205

= 46.099 pounds.

Learn more about density on:

brainly.com/question/11730603

5 0
2 years ago
Which of the following increases the H* concentration in solution?
NNADVOKAT [17]
Acid, I’m pretty sure
6 0
3 years ago
If 3.0 moles of A and 4.0 moles of B react according to the hypothetical reaction below, how many moles of the excess reactant w
blondinia [14]
1 mol of A should be left over
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3 years ago
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Can somebody help with parts c and d
Alecsey [184]

Answer:

13. Na  14. Ne. 15. U. 16. Ca. 17. C. l 18. O.  19. Cl. 20. Si  21. U  22. N.

23. Na 24. Ne. 25. U 26. Sc. 27. N 28. O 29. Cl 30. Si 31. U 32. N.

Explanation:

The general trend as you go to the right in any one period is for the size to decrease.

The general trend is that the size increases as you go down a Group.

The general trend as you go from the bottom left to the top right is a decrease in size.

Ionization energy increases as we move to the right in a period.

It decreases as we move down a group.

Going from the bottom left to top right - the ionization increases.

6 0
3 years ago
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