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2 years ago

Can anyone help me with this?

Chemistry

1 answer:

Scrat [10]2 years ago

5 0

Explanation:

c2H5

cH3 _ c _ c H2 _ c H3

c2H5

cH3

cH3_ cH _ cH_ cH2_ cH3

cH3

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What is the wavelength if the frequency is 29.2 hz?

ZanzabumX [31]

Answer : The wavelength is $1.027\times 10^7m$

Solution : Given,

frequency = 29.2 Hz

Formula used :

$\nu=\frac{c}{\lambda}\\\lambda=\frac{c}{\nu}$

where,

$\nu$ = frequency

$\lambda$ = wavelength

c = speed of light = $3\times 10^8m/s$

Now put all the given values in this formula, we get the wavelength.

$\lambda=\frac{3\times 10^8m/s}{29.2Hz}=0.1027\times 10^8m=1.027\times 10^7m$ $(1Hz=1s^{-1})$

Therefore, the wavelength is $1.027\times 10^7m$

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2 years ago

Solutions can only be separated by using distillation not filtration. Why can't a solution be filtered? Explain using the terms

garri49 [273]

<h2>Solutions</h2>

Explanation:

Solutions are formed when a solute gets dissolved in a solvent. The solid that gets dissolved is called solute whereas the liquid in which the solid gets dissolved is called the solvent. On dissolving, the particles of the solute gets incorporated between the inter-particle space of the solvent. This means that there is no significant difference between the particle size of solute and solvent. However the boiling points of solutions can differ significantly. This is the reason, the solutions cannot be separated by the method of filtration but by the method of distillation.

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3 years ago

Fill in the blank. _______rain falls in areas that have air pollution.

Genrish500 [490]

Acid rain falls in areas that have air pollution. (<span>Acid rain is caused by emissions of </span>sulfur dioxide<span> and </span>nitrogen oxide)

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2 years ago

This is one of the main things I'm having trouble with.

andreev551 [17]

Think it is b
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3 years ago

The K a of propanoic acid ( C 2 H 5 COOH ) is 1.34 × 10 − 5 . Calculate the pH of the solution and the concentrations of C 2 H 5

Zigmanuir [339]

Answer:

2.62.

Explanation:

Okay let us first write the parameters in the question in question above out. We are given the ka value of propanoic acid, C2H5COOH to be equals to 1.34 × 10^- 5. Also, we are given the value for the initial concentration of propanoic acid to be 0.441 M.

So, let us delve right into the solution to the question and we will be starting by writting the equation below;

C2H5COOH <--------> H^+ + C2H5COO^-.

Please note that this Reaction is a reversible Reaction.

Therefore, the basic things about acid is its great tendency to release Hydrogen ion in an aqeous solution.

So, we will be taken equation above and correspond it with the time and Concentration.

C2H5COOH <----> H^+ C2H5COO^-.

Initial concentration of the C2H5COOH = 0.441 M and the initial concentration of H^+ and C2H5COO^- are both zero.

So, after a time, t, concentration of C2H5COOH= 0.441 - x and at that time the concentration of H^+ and C2H5COO^- are both x and x respectively.

Hence, Ka = [C2H5COO^-] [H^+]/ C2H5COOH. -----------------------(**).

Therefore, slotting in the values from above into equation (**), we have;

1.34 × 10^-5 = [x] [x]/ [0.441 - x].

1.34 × 10^-5= x^2/ [0.441 - x].

x^2 = 1.34 × 10^-5(0.441) - 1.34 × 10^-5x.

x^2 + 1.34 × 10^-5x - 5.91× 10^-6.

x = 2.4×10^-3.

Hence, the concentration of the propanoic acid at time, t= 0.441 - 2.4 ×10^-3.

==> 0.44 M.

pH = -log [H^+].

Then, we have; pH= - log[2.4× 10^-3].

pH= 2.62.

4 0

2 years ago